Reputation: 13
val = dict()
def vote(val,person):
if person not in val:
val[person] = 1
else:
val[person] = val[person] + 1
def votes(val,person):
if person in val:
print val[person]
def result(val):
ex = sorted(val.items(), key = lambda val:val[1], reverse=True)
if len(ex) == 0:
print '***NONE***'
#Problem below
elif ex[0] == ex[1]:
print '***NONE***'
else:
print ex[0][0]
Output:
>>>vote(val,'Peter')
>>>vote(val,'Peter')
>>>votes(val,'Peter')
2
>>>vote(val,'Lisa')
>>>vote(val,'Lisa')
>>>votes(val,'Lisa')
2
>>>result(val)
Lisa
>>> print val
{'Lisa': 2, 'Peter': 2}
I want to try to find if 2 keys have the same values, and if they do I want to print "NONE" if that happens. Obviously it doesn't work since it prints "Lisa" instead, any tips on how to do it?
Upvotes: 1
Views: 50
Reputation: 214
In your result function need to check the votes in the elif part.
elif ex[0][1] == ex[1][1]:
print ('***NONE***')
Upvotes: 1