CODEWITHSUNDEEP
python-3.x
alper ortac
alper ortac

Reputation: 49

Printing even characters with strings in python

s = 'Abrakadabra'
for k in (len(s)):
  if (k%2==1):
    print(s[k])

This code doesn't work, what is the problem?

Upvotes: 0

Views: 4545

Answers (3)

Averner
Averner

Reputation: 130

You are trying to iterate through int (len(s)) i think you're just simply missing the range function

s = 'Abrakadabra'
for k in range(len(s)):
  if k%2==1:
    print(s[k])

also much simlpler version is could be done with:

>>> s[1::2]
'baaar'

let's break it down:

s[1: :2]
^ ^ ^ ^
|-|-|-|--- string to use
  |-|-|--- index to start from (1 for even, zero or ' ' for odd)
    |-|--- index to stop at - space means "till the end"
      |----step to take - 2 for every second, 3 for every third and so on

Upvotes: 4

Jae Yang
Jae Yang

Reputation: 539

You want to iterate over the range of len(s) 

s = 'Abrakadabra'
for k in range(len(s)):
  if (k%2==1):
    print(s[k])

and even easier pythonic way is

print(s[1::2])

Upvotes: 1

hiro protagonist
hiro protagonist

Reputation: 46901

you are missing the range to iterate over: for k in range(len(s)):...

you could also use enumerate:

s = 'Abrakadabra'

for i, x in enumerate(s):
    if i % 2 == 1:
        print(x)

Upvotes: 0

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