CODEWITHSUNDEEP
pythonargparse
Sabrina
Sabrina

Reputation: 103

How to pass a variable into argparse in python

I have a python script func.py that contains argparse and takes a file

parser = argparse.ArgumentParser(description='test')
parser.add_argument('-i', dest='ifile', metavar="FILE", help='input file')
args = parser.parse_args()

This ifile is basically just a name of that file in a directory

filename = 'PATH TO FILE' + args.ifile

If I have a variable that contains the name of the file how can I pass the variable to the argparse so that it would take the string value of the variable? Something like this : 

new_file = 'text_file.txt'
func.py -i new_file
filename = 'PATH TO FILE' + 'text_file.txt'

What I am getting now is this:

new_file = "text_file.txt'
python func.py -I new_file
filename = 'PATH TO FILE' + 'new_file'

And then obviously an error message that it cannot find the file.

Upvotes: 1

Views: 410

Answers (1)

l'L'l
l'L'l

Reputation: 47169

You should simply be able to do:

$ new_file="text_file.txt"
$ ./func.py -I $new_file

Your args variable in Python should then contain ifile='text_file.txt':

text_file.txt

Upvotes: 2

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