smart pointer with unexpected behavior

Question

As i was going through smart pointers, I ran through the following code.

Works as expected.

#include <iostream>
#include <memory>

using namespace std;

class Double
{
public:
    Double(double d = 0) : dValue(d) { cout << "constructor: " << dValue << endl; } 
    ~Double() { cout << "destructor called with exception: " << dValue << endl; }
    void setDouble(double d) { dValue = d; 
        float temp= d/0;
        cout<<"Error\n";
    }
private:
    double dValue;
}; 

int main()
{
    auto_ptr<Double> ptr(new Double(3.14));
    (*ptr).setDouble(6.28); 

    return 0;
}

As you can see there is an exception in setDouble method i.e i am trying divided by zero, since i am using the auto_ptr here even though there is the exception the allocated object for the class Double will be destroyed and destructor will be called this is as expected. But i have encountered one issue when i changed the code snippet, instead of dividing the d by zero, i use hard code value 1 and divide it by zero in this case also this is an exception, but as i am using auto pointer i was expecting the allocated object to be deleted, for my surprise the exception occurs and object of Double is not destroyed.

Not expected behavior.

#include <iostream>
#include <memory>

using namespace std;

class Double
{
public:
    Double(double d = 0) : dValue(d) { cout << "constructor: " << dValue << endl; } 
    ~Double() { cout << "destructor called with exception: " << dValue << endl; }
    void setDouble(double d) { dValue = d; 
        float temp= 1/0;
        cout<<"Error\n";
    }
private:
    double dValue;
}; 

int main()
{
    auto_ptr<Double> ptr(new Double(3.14));
    (*ptr).setDouble(6.28); 

    return 0;
}

Can anyone help me to understand this, why it is not behaving as expected when i hard code 1/0 in the setDouble method.

Thank you.