CODEWITHSUNDEEP
pythonpython-3.xstring
Jake Rankin
Jake Rankin

Reputation: 744

How to make only part of a string uppercase?

I have strings which are incomplete URLs, like the following:

"dl_image/cm1111.jpg"
"dl_image/CM2222.jpg"

The problem is, the second is correct, the first is not. The letters between the numbers and 'dl_image/' must always be uppercase.

I am using joinging these incomplete urls onto a base url using urljoin with the following code:

imagehtml = temp1['dl_image']
if temp1.get('set') != None:
    if imagehtml != None and imagehtml !='':
        soup = Soup(imagehtml, 'html.parser')
        for a in soup.find_all('a', href=True):
            print(urljoin(base_url, a['href']))

imagehtml contains the incomplete urls.

Is there a way to convert only these letters to uppercase, and not the extension or directory?

Upvotes: 1

Views: 131

Answers (5)

Rohit-Pandey
Rohit-Pandey

Reputation: 2159

Try This One:

import re
a = 'dl_image/cm12345/cm12.jpg'
b = len(a)-1-a[::-1].index('/')
c = a[b:]
d = re.findall(r"\d+",c)
if len(d)>0:
  e = a.index(d[0], b)
  f = a[:b+1]+a[b+1:e].upper()+a[e:]
  print(f)

Output:

dl_image/cm12345/CM12.jpg

Upvotes: 0

SpghttCd
SpghttCd

Reputation: 10850

Perhaps you like

url = 'dl_image/cm1111.jpg'

path, file = url.rsplit('/', 1)
name, ext = file.rsplit('.', 1)
print(path + '/' + name.upper() + '.' + ext)

I.e. split only at the rightmost '/' and '.' to then uppercase only the portion in between these two positions.

Upvotes: 2

ycx
ycx

Reputation: 3211

I personally would recommend using str.rfind() because the pattern in your cases will typically involve a . near the very end as your file extension and a / before the very end as your beginning of the conversion you are trying to do to your filename string. See the code below:

s="dl_image/cm2222.jpg"
start = s.rfind('/')
end = s.rfind('.')
new_s = s[:start] + s[start:end].upper() + s[end:]
print (new_s) 
#dl_image/CM2222.jpg

Upvotes: 2

U13-Forward
U13-Forward

Reputation: 71560

Use a str.join with list comprehension as parameter, doing conditions and doing expected stuff:

>>> s="dl_image/cm1111.jpg"
>>> ''.join([v.upper() if s[i-1]=='/' or s[i-2]=='/' else v for i,v in enumerate(s)])
'dl_image/CM1111.jpg'
>>>

Update:

imagehtml = temp1['dl_image']
if temp1.get('set') != None:
    if imagehtml != None and imagehtml !='':
        soup = Soup(imagehtml, 'html.parser')
        for a in soup.find_all('a', href=True):
            print(urljoin(base_url, ''.join([v.upper() if a['href'][i-1]=='/' or a['href'][i-2]=='/' else v for i,v in enumerate(a['href'])])))

Upvotes: 2

Rachit Bhargava
Rachit Bhargava

Reputation: 168

Yes, that's easy. Here's a way to do it:

  1. Find index of the last /.
  2. Find index of the place from where the extension starts.
  3. Convert everything between the two indexes to upper case.

Here's a way you can translate it into code:

test_url = "dl_image/cm1111.jpg"
last_slash_index = test_url.rfind('/')
extension_start_index = test_url.rfind('.')
final_url = test_url[:last_slash_index+1] + test_url[last_slash_index+1:extension_start_index].upper() + test_url[extension_start_index:]

Upvotes: 1

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