CODEWITHSUNDEEP
androidandroid-image
Badr Hari
Badr Hari

Reputation: 8384

Open an image using URI in Android's default gallery image viewer

I have extracted image uri, now I would like to open image with Android's default image viewer. Or even better, user could choose what program to use to open the image. Something like File Explorers offer you if you try to open a file.

Upvotes: 100

Views: 187368

Answers (15)

user28952305
user28952305

Reputation: 1

The answer above using bucketid is close, however in modern versions of Android it appears you require MediaStore.ACTION_REVIEW instead of Intent.ACTION_VIEW

Would add a comment but need 50 reputation

Upvotes: 0

android developer
android developer

Reputation: 116372

If your app targets Android N (7.0) and above, you should not use the answers above (of the "Uri.fromFile" method), because it won't work for you.

Instead, you should use a ContentProvider.

For example, if your image file is in external folder, you can use this (similar to the code I've made here) :

File file = ...;
final Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setDataAndType(VERSION.SDK_INT >= VERSION_CODES.N ? FileProvider.getUriForFile(this,getPackageName() + ".provider", file) : Uri.fromFile(file), "image/*");
intent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
startActivity(intent);

manifest:

<provider
    android:name="androidx.core.content.FileProvider"
    android:authorities="${applicationId}.provider"
    android:exported="false"
    android:grantUriPermissions="true">
    <meta-data
        android:name="android.support.FILE_PROVIDER_PATHS"
        android:resource="@xml/provider_paths"/>
</provider>

res/xml/provider_paths.xml :

<?xml version="1.0" encoding="utf-8"?>
<paths>
    <!--<external-path name="external_files" path="."/>-->
    <external-path
        name="files_root"
        path="Android/data/${applicationId}"/>
    <external-path
        name="external_storage_root"
        path="."/>
</paths>

If your image is in the private path of the app, you should create your own ContentProvider, as I've created "OpenFileProvider" on the link.

Upvotes: 42

Ahmet B.
Ahmet B.

Reputation: 1674

The uri must be content uri not file uri, You can get contentUri by FileProvider as

Uri contentUri = FileProvider.getUriForFile(getContext(),"com.github.myApp",curFile);

Don't forget adding provider in Manifest file.

<provider
        android:name="androidx.core.content.FileProvider"
        android:authorities="com.github.myApp"
        android:exported="false"
        android:grantUriPermissions="true">
        <meta-data
            android:name="android.support.FILE_PROVIDER_PATHS"
            android:resource="@xml/provider_paths" />
</provider>

Upvotes: 0

creativecoder
creativecoder

Reputation: 1540

My solution using File Provider

    private void viewGallery(File file) {

 Uri mImageCaptureUri = FileProvider.getUriForFile(
  mContext,
  mContext.getApplicationContext()
  .getPackageName() + ".provider", file);

 Intent view = new Intent();
 view.setAction(Intent.ACTION_VIEW);
 view.setData(mImageCaptureUri);
 List < ResolveInfo > resInfoList =
  mContext.getPackageManager()
  .queryIntentActivities(view, PackageManager.MATCH_DEFAULT_ONLY);
 for (ResolveInfo resolveInfo: resInfoList) {
  String packageName = resolveInfo.activityInfo.packageName;
  mContext.grantUriPermission(packageName, mImageCaptureUri, Intent.FLAG_GRANT_WRITE_URI_PERMISSION | Intent.FLAG_GRANT_READ_URI_PERMISSION);
 }
 view.addFlags(Intent.FLAG_GRANT_WRITE_URI_PERMISSION);
 Intent intent = new Intent();
 intent.setAction(Intent.ACTION_VIEW);
 intent.setDataAndType(mImageCaptureUri, "image/*");
 mContext.startActivity(intent);
}

Upvotes: 2

knightcube
knightcube

Reputation: 159

My solution 

Intent intent = new Intent();
intent.setAction(Intent.ACTION_VIEW);
intent.setDataAndType(Uri.fromFile(new File(Environment.getExternalStorageDirectory().getPath()+"/your_app_folder/"+"your_picture_saved_name"+".png")), "image/*");
context.startActivity(intent);

Upvotes: 0

IgniteCoders
IgniteCoders

Reputation: 4980

The problem with showing a file using Intent.ACTION_VIEW, is that if you pass the Uri parsing the path. Doesn't work in all cases. To fix that problem, you need to use:

Uri.fromFile(new File(filePath));

Instead of:

Uri.parse(filePath);

Edit

Here is my complete code:

Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setDataAndType(Uri.fromFile(new File(mediaFile.filePath)), mediaFile.getExtension());
intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);

Info

MediaFile is my domain class to wrap files from database in objects. MediaFile.getExtension() returns a String with Mimetype for the file extension. Example: "image/png"

Aditional code: needed for showing any file (extension)

import android.webkit.MimeTypeMap;

public String getExtension () {
    MimeTypeMap myMime = MimeTypeMap.getSingleton();
    return myMime.getMimeTypeFromExtension(MediaFile.fileExtension(filePath));
}

public static String fileExtension(String path) {
    if (path.indexOf("?") > -1) {
        path = path.substring(0, path.indexOf("?"));
    }
    if (path.lastIndexOf(".") == -1) {
        return null;
    } else {
        String ext = path.substring(path.lastIndexOf(".") + 1);
        if (ext.indexOf("%") > -1) {
            ext = ext.substring(0, ext.indexOf("%"));
        }
        if (ext.indexOf("/") > -1) {
            ext = ext.substring(0, ext.indexOf("/"));
        }
        return ext.toLowerCase();
    }
}

Let me know if you need more code.

Upvotes: 4

baswaraj
baswaraj

Reputation: 639

This thing might help if your working with android N and below

 File file=new File(Environment.getExternalStorageDirectory()+"/directoryname/"+filename);
        Uri path= FileProvider.getUriForFile(MainActivity.this,BuildConfig.APPLICATION_ID + ".provider",file);

        Intent intent=new Intent(Intent.ACTION_VIEW);
        intent.setDataAndType(path,"image/*");
        intent.setFlags(FLAG_GRANT_READ_URI_PERMISSION | FLAG_GRANT_WRITE_URI_PERMISSION); //must for reading data from directory

Upvotes: 12

Ranjithkumar
Ranjithkumar

Reputation: 18386

All the above answers not opening image.. when second time I try to open it show the gallery not image.

I got solution from mix of various SO answers.. 

Intent galleryIntent = new Intent(Intent.ACTION_VIEW, android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
galleryIntent.setDataAndType(Uri.fromFile(mImsgeFileName), "image/*");
galleryIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(galleryIntent);

This one only worked for me..

Upvotes: 4

Joaquin Iurchuk
Joaquin Iurchuk

Reputation: 5617

Based on Vikas answer but with a slight modification: The Uri is received by parameter:

private void showPhoto(Uri photoUri){
    Intent intent = new Intent();
    intent.setAction(Intent.ACTION_VIEW);
    intent.setDataAndType(photoUri, "image/*");
    startActivity(intent);
}

Upvotes: 18

TeeTracker
TeeTracker

Reputation: 7350

Almost NO chance to use photo or gallery application(might exist one), but you can try the content-viewer.

Please checkout another answer to similar question here

Upvotes: 0

Muhammad Aamir Ali
Muhammad Aamir Ali

Reputation: 21097

I use this it works for me

Intent intent = new Intent();
intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent,
"Select Picture"), 1);

Upvotes: 3

Christopher Perry
Christopher Perry

Reputation: 39225

A much cleaner, safer answer to this problem (you really shouldn't hard code Strings):

public void openInGallery(String imageId) {
  Uri uri = MediaStore.Images.Media.EXTERNAL_CONTENT_URI.buildUpon().appendPath(imageId).build();
  Intent intent = new Intent(Intent.ACTION_VIEW, uri);
  startActivity(intent);
}

All you have to do is append the image id to the end of the path for the EXTERNAL_CONTENT_URI. Then launch an Intent with the View action, and the Uri.

The image id comes from querying the content resolver.

Upvotes: 6

Eugene
Eugene

Reputation: 221

Try use it:

Uri uri =  Uri.fromFile(entry);
Intent intent = new Intent(android.content.Intent.ACTION_VIEW);
String mime = "*/*";
MimeTypeMap mimeTypeMap = MimeTypeMap.getSingleton();
if (mimeTypeMap.hasExtension(
    mimeTypeMap.getFileExtensionFromUrl(uri.toString())))
    mime = mimeTypeMap.getMimeTypeFromExtension(
        mimeTypeMap.getFileExtensionFromUrl(uri.toString()));
intent.setDataAndType(uri,mime);
startActivity(intent);

Upvotes: 22

Vikas
Vikas

Reputation: 24322

Accepted answer was not working for me,

What had worked:

Intent intent = new Intent();
intent.setAction(Intent.ACTION_VIEW);
intent.setDataAndType(Uri.parse("file://" + "/sdcard/test.jpg"), "image/*");
startActivity(intent);

Upvotes: 181

Badr Hari
Badr Hari

Reputation: 8384

Ask myself, answer myself also:

startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("content://media/external/images/media/16"))); /** replace with your own uri */

It will also ask what program to use to view the file.

Upvotes: 34

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