Reputation: 1518
I have a method that returns a Future[Boolean] in a Play controller and i want to evaluate that using async but i can't seem to get it to compile. The following will work:
def health = Action {
logger.info("Endpoint method: health")
val isHealthy = healthCheckService.checkDynamo()
val b: Boolean = Await.result(isHealthy, scala.concurrent.duration.Duration(5, "seconds"))
Ok(Json.toJson(HealthCheckResponse(b.toString)))
}
But i don't think i want that Await in there. So i'm trying things like this with no success:
def health =
Action.async {
Future {
logger.info("Endpoint method: health")
healthCheckService.checkDynamo() match {
case Future.successful(true) => Ok(Json.toJson("false"))
case false => Ok(Json.toJson("true"))
}
val r = healthCheckService.checkDynamo() match {
case true => Ok(Json.toJson("false"))
case false => Ok(Json.toJson("true"))
}
}
}
I can't even get those to compile to test them out. Any suggestions?
Upvotes: 0
Views: 804
Reputation: 2582
Try this:
def health = Action.async {
healthCheckService.checkDynamo().map {
case true => Ok(Json.toJson("false"))
case false => Ok(Json.toJson("true"))
}
}
Let Play handle the awaiting for you under the hood. That is, Action.async
accepts a Future
, which checkDynamo()
already returns. All you have to do is map
it to the appropriate result.
Upvotes: 2
Reputation: 128111
With Futures
you have to use combinators like map
and flatMap
to express the final value. For example:
Action.async {
healthCheckService.checkDynamo()
.map { result => // boolean
HealthCheckResponse(result.toString)
}
.map(Json.toJson(_))
.map(Ok(_))
}
(You can merge map
s above to one map
and construct the final Ok
value there; it is more or less a matter of taste)
If you have, say, two async calls which you want to execute and return a result based on their results, you can use flatMap
, which could be easily expressed using a for
comprehension:
Action.async {
for {
result1 <- someService.someCall()
result2 <- anotherService.anotherCall(result1.someProperty)
finalResult = SomeFinalResultType(result1, result2)
} yield Ok(Json.toJson(finalResult))
}
If you are not familiar with futures, you might want to read some tutorial which explains their nature, how to combine them and how to get useful results from them, like this one: http://hello-scala.com/920-scala-futures.html
Upvotes: 2