CODEWITHSUNDEEP
iphoneobjective-cios
Justin
Justin

Reputation: 315

Passing argument makes pointer from integer without a cast

I wrote a function that looks like this:

- (void)changeText:(NSUInteger)arrayIndex;

Let's just say that's a method in the class Label. Let's say I have an array of Label objects. I call the function like this:

[[labels objectAtIndex:0] changeText:1];

or like this:

NSUInteger index = 1;
[[labels objectAtIndex:0] changeText:index];

Why does it give me the warning: Passing argument 1 of 'changeText:' makes pointer from integer without a cast? The code executes fine.

*EDIT*

Calling the function these ways does not give a warning:

[[labels objectAtIndex:0] changeText:0]; //arrayIndex is 0

Label *object = [labels objectAtIndex:0];
[object changeText:1];

Upvotes: 2

Views: 2361

Answers (2)

Vagrant
Vagrant

Reputation: 1716

Somehow it thinks that changeText: takes a pointer as an argument. Probably because objectAtIndex: returns an NSObject and Objective-C doesn't know, a priori, what class's signature to apply to it.

Why don't you assign the result of objectAtIndex: to a Label*, then apply changeText: to it?

Like so: Label* label = (Label *)[labels objectAtIndex:0]; [label changeText:1];

Upvotes: 2

bbum
bbum

Reputation: 162722

More likely than not, you aren't #importing the header file containing the definition of changeText: into whatever .m file is calling it and, thus, the compiler hasn't seen the method declaration and doesn't know what the argumentation is supposed to be.

Or you have a changeText: method defined that does take an object reference as an argument and the compiler is seeing that before compiling the call site.

Upvotes: 5

Related Questions