Reputation: 101
I'm new to Matlab and I wonder how to input a vector to a symbolic function. It is said in the document that creating vectors by x = sym('x',[50 1])
and use it for generate objective function f(x)
, but it doesn't work if I want to test the value of function when x = ones(50,1) since the input expects 50 variables.
How can I change my code to achieve that?
m = 100;
n = 50;
A = rand(m,n);
b = rand(m,1);
c = rand(n,1);
% initialize objective function
syms x
f = symfun([c'* x - sum(log(A*x + b))],x);
tolerance = 1e-6
% Max iterations
N =1000;
% start point
xstart = ones(n,1)
% Method: gradient descent
% store step history
xg = zeros(n,N);
% initial point
xg(:,1) = xstart;
fprintf('Starting gradient descent.')';
for k = 1:(N-1)
d = - gradient(f,xg(:,k));
if norm(d) < tolearance
xg = xg(:,1:k);
break;
end
Upvotes: 0
Views: 445
Reputation: 364
I think you misunderstood the line x = sym('x',[50 1]). It would create 50 symbolic variables starting from x1 to x50 within the workspace. But I think you need 1 variable x to be defined within the workspace and later you can use that x to create a function such that you may call that function passing a vector of size 50 to it to get the corresponding fx values.
If you want the function to be evaluated at all the values of x then you need to use the function subs(fx, x_points).
The sample code is given below.
clc
clear all
m = 10;
n = 10;
A = rand(m,n);
b = rand(m,1);
c = rand(n,1);
% declare the symbolic x variable
syms x
% declare the function
f = symfun(c'* x - sum(log(A*x + b)), x);
% declare the x data points
x_points = ones(10,1);
% substituting the x points within the f(x)
evaluated_fx = subs(f, x_points)
% *********** perform the further operations below with the evaluated_fx
Please ensure that you use the dot(.) operator correctly while declaring a symbolic function otherwise you may get unexpected results with incorrect resulting dimensions.
Upvotes: 0