Reputation: 7841
I have table like this
id col1 col2
1 A 1
2 B 0
3 A 1
4 C 1
5 B 0
6 A 0
7 C 1
8 C 1
9 B 1
10 B 0
I need a query something like this
Values 1 0
A 2 1
B 1 3
C 3 0
In the above result the header shows the col2
distinct values (1,0)
and rows names represents distinct values of col1
. The values in the table shows the counts.
Any suggestion to get the result like this in postgresql?
Upvotes: 1
Views: 62
Reputation: 11155
You could also use FILTER:
SELECT
col1,
COUNT(*) FILTER (WHERE col2 = 1) AS 1,
COUNT(*) FILTER (WHERE col2 = 0) AS 0,
FROM
foo
GROUP BY
col1;
Upvotes: 1
Reputation: 1270873
Here are simpler ways to write this logic. The first is Postgres-specific:
select col1,
sum( (col2 = 1)::int ) as num_1,
sum( (col2 = 0)::int as num_0
from t
group by col1;
The second just uses arithmetic:
select col1,
sum( col2 ) as num_1,
sum( 1 - col2 ) as num_0
from t
group by col1;
Upvotes: 0
Reputation: 50173
You need conditional aggregation :
select col1,
sum(case when col2 = 1 then 1 else 0 end) as 1,
sum(case when col2 = 0 then 1 else 0 end) as 0
from table t
group by col1;
Upvotes: 2