CODEWITHSUNDEEP
javalogical-operators
Wardi
Wardi

Reputation: 21

sequence of actions in the logical expression

I want to ask about correct sequence "reading" of this logical expression:

(true && false | true)

I thought it returns false, because of first expression - true && false But probably I'm doing something wrong and it's should be "reading" another way. Can you explain what's correct way to reading it?

Upvotes: 1

Views: 89

Answers (2)

Shivang Agarwal
Shivang Agarwal

Reputation: 1923

By keeping below the point in the notice:

All binary operators except for the assignment operators are evaluated from left to right; assignment operators are evaluated right to left.

This will be get executed from left to right. After that 2nd point to consider is Operator Precedence.

| is a bitwise operator and && is a logical operation. the bitwise operator has more priority than the logical operator.

In your case, the first evaluation will be false | true which is true.

then it will evaluate the true && result of above which is true.

so the given statement will be true.

Upvotes: 1

Eran
Eran

Reputation: 393956

Check the following table of Operators Precedence.

| (bitwise inclusive OR) has higher precedence than && (logical AND), so false | true is evaluated first.

That said, the evaluation order doesn't matter in your example. Both (true && false) | true and true && (false | true) return true. In the first case it's false | true), which is true. In the second case it's true && true, which is also true.

Now, here's an example where the operator precedence makes a difference:

System.out.println (false && true | true);
System.out.println (false && true || true);

| has a higher precedence than &&, but && has a higher precedence than ||.

Therefore these expressions are evaluated as:

System.out.println (false && (true | true));
System.out.println ((false && true) || true);

As a result, the first returns false and the second returns true.

Upvotes: 1

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