CODEWITHSUNDEEP
pythonregex
Fasty
Fasty

Reputation: 804

How can I get the regex equivalent if the expression are in separate lines?

I have the following string:

Datum Kundnummer Sida
2018-10-12 196979 1 /2

The two strings above are in separate lines

What is the regex equivalent so that I get the following output?

Datum 2018-10-12
Kundnummer 196979

The above two are separate outputs

I want the output such that it works for all dates in datum and all numbers in Kundnummer.

I tried Datum\s([12]\d{3}-(0[1-9]|1[0-2])-(0[1-9]|[12]\d|3[01])) and Kundnummer\s(\d+).

Upvotes: 1

Views: 85

Answers (3)

David3103
David3103

Reputation: 133

I assume the data in the first line is always the same, so I'd ignore it.

To get the "Datum" and "Kundennummer" entries from the second line, use (?P<datum>\d{4}\-\d{1,2}\-\d{1,2})\s(?P<kundennummer>\d+?).*.

As @PyHunterMan explained, you could also just split the string at the whitespaces. That would probably be the easier way.

Upvotes: 0

Andie2302
Andie2302

Reputation: 4887

I suggest something like this:

reobj = re.compile(r"(?P<datum>\d{4}-\d{1,2}-\d{1,2})\s+(?P<kundnummer>\d+)")
match = reobj.search(input)
if match:
    result1 = match.group("datum")
    result2 = match.group("kundnummer")

Upvotes: 0

user10732646
user10732646

Reputation:

Why would you wage on time figuring this out when you can do it in a simple lines of code without regex.

_input = "Datum Kundnummer Sida\n2018-10-12 196979 1 /2"
lines = _input.split('\n')
old_line_one, old_line_two = lines[0].split(), lines[1].split()
new_line_one = f'{old_line_one[0]} {old_line_two[0]}'
new_line_two = f'{old_line_one[1]} {old_line_two[1]}'
print(f'{new_line_one}\n{new_line_two}')

Upvotes: 1

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