CODEWITHSUNDEEP
bash
moimoi
moimoi

Reputation: 201

Explode a number in bash

How would I explode out a number in bash

With this value '12684041234'

Required result '12684041234','1268404123','126840412','12684041','1268404','126840','12684','1268','126','12','1'

Upvotes: 0

Views: 162

Answers (8)

ctac_
ctac_

Reputation: 2491

with dc :

echo '12684041234' | dc -f - -e '[p10/d0<Z]sZlZx'

explanation :

# -f - is the file to read for the input (/dev/stdin)
# -e '...' is the code to execute

echo '12684041234' | dc -f - -e '
[
p       # print the stack
10
/       # divide the stack by 10
d       # duplicate the result
0
<Z      # while the stack is greater than 0 execute macro Z
] sZ    # define macro Z inside [ ]
lZ      # load macro Z
x       # execute it
'

Upvotes: 1

stack0114106
stack0114106

Reputation: 8711

Using Perl and regex

$ echo '12684041234' | perl -ne  ' $x=$_;$i=length($x); while($i>0) { $x=~m/(.{$i})/m; print "$1\n" ; $i-- } '

12684041234
1268404123
126840412
12684041
1268404
126840
12684
1268
126
12
1

Thanks to Nahuel for the below solution

perl -nE '/^.+(?{say$&})(?!)/' <<<12684041234

Upvotes: 1

mickp
mickp

Reputation: 1809

sed solution for fun:

$ sed -n ':a;p;s/.$//;/./ba' <<< 12684041234
12684041234
1268404123
126840412
12684041
1268404
126840
12684
1268
126
12
1

Upvotes: 1

Jay jargot
Jay jargot

Reputation: 2868

The % can be used to remove prefix of a variable's value.

Give a try to this:

number=12684041234
while [[ "${#number}" -gt 0 ]] ; do
    printf ",'%s'" "${number}"
    number="${number%?}"
done | cut -b 2-

Output

'12684041234','1268404123','126840412','12684041','1268404','126840','12684','1268','126','12','1'

Upvotes: 2

Carlos Mesquita Aguiar
Carlos Mesquita Aguiar

Reputation: 19

I ain't thinkin' good practices, but to solver this problem. Here's how in Python the solution would be:

from functools import reduce

def f_split_word(s_word):
    return s_word

def f_list_explode_word(s_word):
    ret = []
    s_word_split = list(map(f_split_word, s_word))
    for x in range(0, len(s_word_split)):
        ret.append(reduce(lambda x,y: str(x) + str(y), s_word_split if x == 0 else s_word_split[:-x]))   
    return ret

s_word = str('12684041234')
print(f_list_explode_word(s_word))

enter image description here

Upvotes: -1

Nahuel Fouilleul
Nahuel Fouilleul

Reputation: 19315

if n is less than or equals echo $((2**63-1))

for((n=12684041234;n>0;n/=10));do echo $n;done

Upvotes: 2

James Brown
James Brown

Reputation: 37424

Using GNU awk:

$ echo 12684041234 | awk 'BEGIN{FS=OFS=""}{for(i=NF;i>=1;i--){print;NF--}}'
12684041234
1268404123
126840412
...

Upvotes: 1

Tom Fenech
Tom Fenech

Reputation: 74685

I don't think that there's any built-in way to do what you want, but you can always use a loop:

n=12684041234
for (( i = ${#n}; i > 0; i-- )) do echo ${n:0:i}; done

This just loops from the length of the variable $n down to 1 and prints substrings of $n.

Upvotes: 3

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