CODEWITHSUNDEEP
functionrustnestedarguments
Mano
Mano

Reputation: 99

How can I avoid passing a lot of parameters into a nested function?

I have read that there is no way how to pass all outer local parameters to a nested function, but maybe there are some hacks to do it anyway? How can I avoid passing a lot of parameters into this function, for example:

let var1 = 5;
let var2 = 12.2;
let var3 = bar();
let var4 = tar() * var1;
// etc ... a lot of variables ...
fn foo() {
    // want to have var1, var2, var3, var4 ...
}

Upvotes: 0

Views: 584

Answers (1)

Denys Séguret
Denys Séguret

Reputation: 382160

What you want is called a closure:

fn main() {
    let var1 = 5;
    let var2 = 12.2;
    let foo = || {
        var1 as f64 + var2
    };
    println!("foo(): {}", foo()); // prints "foo(): 17.2"
}

Upvotes: 4

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