CODEWITHSUNDEEP
scalaplayframework
S. Meziani
S. Meziani

Reputation: 61

How to pass a Future data to the view?

Iam trying to get data from a web weather API, I'am getting the data by using WSClient.

Actually, I can println and visualize the data like this : 

val futureResponse: Future[WSResponse] = complexRequest.get()

def weather = Action {
   futureResponse.map {
     response =>
       println(response.json)
   }
   println(futureResponse)

   Ok(views.html.weather("data"))
}

but I have trouble passing it to the view layer using Ok(views.html.weather("data")) cause when i println(futureResponse) its not json data it shows : Future(Success(AhcWSResponse(StandaloneAhcWSResponse(200, OK))))

only println(response.json) shows the valid data i want to send but its unreachable outside.

Upvotes: 0

Views: 183

Answers (2)

ultrasecr.eth
ultrasecr.eth

Reputation: 1497

You need something on the lines of

def weather = Action.async {
   complexRequest.get().map(response => Ok(views.html.weather(response.json)))
}

So basically, the json is only available when the future is completed, so you can only pass it to the view inside the map function, also notice that I've used Action.async this creates an action that expects a Future[WsResponse] rather than just a WsResponse

Also bear in mind that the Futures are memoised, so if you store the reference to it in a val it will only execute once

EDIT: Fixed the future being stored in a val to avoid problems with the memoisation

Upvotes: 2

Raj Parekh
Raj Parekh

Reputation: 192

It's unreachable because you will have to use a callback method to access/pass the content inside Future. That's the reason println(response.json) inside map callback shows the data/content you are interested.

You may refer to Accessing value returned by scala futures

Upvotes: 0

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