Reputation: 109
I would like to indicate the starting point of the graph - where the line started. This is my code
import numpy as np
from scipy.integrate import odeint
from numpy import sin, cos, pi, array
import matplotlib
from matplotlib import rcParams
import matplotlib.pyplot as plt
from pylab import figure, axes, title, show
import xlsxwriter
def deriv(z, t):
l = 0.3 #unextended length of the spring, in m
m = 1 #mass of the bob, in kg
k = 1 #spring constant, in Nm^-1
g = 9.81 #gravitational acceleration, in ms^-2
x, y, dxdt, dydt = z
dx2dt2 = (l+x)*(dydt)**2 - k/m*x + g*cos(y)
dy2dt2 = (-g*sin(y) - 2*(dxdt)*(dydt))/(l+x)
#equations of motion
return np.array([dxdt, dydt, dx2dt2, dy2dt2])
init = array([0.3, pi/2, 0.0, 2])
#initial conditions (x, y, xdot, ydot)
time = np.linspace(0, 100, 10000)
#time intervals (start, end, number of intervals)
sol = odeint(deriv, init, time)
#solving the equations of motion
x = sol[:,0]
y = sol[:,1]
l = 0.3 #unextended length of the spring, in m
n = (l+x) * sin(y)
u = -(l+x) * cos(y)
#converting x and y to Cartesian coordinates
plt.plot(n,u)
plt.xlabel('$n$ (m)')
plt.ylabel('$u$ (m)')
plt.title('$n$ versus $u$ for 'r'$\theta_0 = \frac{\pi}{2}+0.001$')
plt.show()
Thank you!
Upvotes: 1
Views: 61
Reputation: 1895
Plotting the first point can be done by adding plt.plot(n[0], u[0], '*') to your code, see below.
Full documentation for the plot function (thanks for the comment mostlyoxygen), to get a better idea of how you can change the colour, size and shape of the dot.
from scipy.integrate import odeint
from numpy import array, linspace, sin, cos, pi, array
from matplotlib import rcParams
import matplotlib.pyplot as plt
def deriv(z, t):
l = 0.3 #unextended length of the spring, in m
m = 1 #mass of the bob, in kg
k = 1 #spring constant, in Nm^-1
g = 9.81 #gravitational acceleration, in ms^-2
x, y, dxdt, dydt = z
dx2dt2 = (l+x)*(dydt)**2 - k/m*x + g*cos(y)
dy2dt2 = (-g*sin(y) - 2*(dxdt)*(dydt))/(l+x)
#equations of motion
return array([dxdt, dydt, dx2dt2, dy2dt2])
init = array([0.3, pi/2, 0.0, 2])
#initial conditions (x, y, xdot, ydot)
time = linspace(0, 100, 10000)
#time intervals (start, end, number of intervals)
sol = odeint(deriv, init, time)
#solving the equations of motion
x = sol[:,0]
y = sol[:,1]
l = 0.3 #unextended length of the spring, in m
n = (l+x) * sin(y)
u = -(l+x) * cos(y)
#converting x and y to Cartesian coordinates
plt.plot(n,u)
plt.plot(n[0], u[0], '*')
plt.xlabel('$n$ (m)')
plt.ylabel('$u$ (m)')
plt.title('$n$ versus $u$ for 'r'$\theta_0 = \frac{\pi}{2}+0.001$')
plt.show()
Upvotes: 4