Reputation: 8577
I have the following:
Vec<&str>
.&str
that may contain $0
, $1
, etc. referencing the elements in the vector.I want to get a version of my &str
where all occurences of $i
are replaced by the ith element of the vector. So if I have vec!["foo", "bar"]
and $0$1
, the result would be foobar
.
My first naive approach was to iterate over i = 1..N
and do a search and replace for every index. However, this is a quite ugly and inefficient solution. Also, it gives undesired outputs if any of the values in the vector contains the $
character.
Is there a better way to do this in Rust?
Upvotes: 0
Views: 802
Reputation: 8577
This solution is inspired (including copied test cases) by Shepmaster's, but simplifies things by using the replace_all
method.
use regex::{Regex, Captures};
fn template_replace(template: &str, values: &[&str]) -> String {
let regex = Regex::new(r#"\$(\d+)"#).unwrap();
regex.replace_all(template, |captures: &Captures| {
values
.get(index(captures))
.unwrap_or(&"")
}).to_string()
}
fn index(captures: &Captures) -> usize {
captures.get(1)
.unwrap()
.as_str()
.parse()
.unwrap()
}
fn main() {
assert_eq!("ab", template_replace("$0$1", &["a", "b"]));
assert_eq!("$1b", template_replace("$0$1", &["$1", "b"]));
assert_eq!("moo", template_replace("moo", &[]));
assert_eq!("abc", template_replace("a$0b$0c", &[""]));
assert_eq!("abcde", template_replace("a$0c$1e", &["b", "d"]));
println!("It works!");
}
Upvotes: 3
Reputation: 430681
I would use a regex
use regex::Regex; // 1.1.0
fn example(s: &str, vals: &[&str]) -> String {
let r = Regex::new(r#"\$(\d+)"#).unwrap();
let mut start = 0;
let mut new = String::new();
for caps in r.captures_iter(s) {
let m = caps.get(0).expect("Regex group 0 missing");
let d = caps.get(1).expect("Regex group 1 missing");
let d: usize = d.as_str().parse().expect("Could not parse index");
// Copy non-placeholder
new.push_str(&s[start..m.start()]);
// Copy placeholder
new.push_str(&vals[d]);
start = m.end()
}
// Copy non-placeholder
new.push_str(&s[start..]);
new
}
fn main() {
assert_eq!("ab", example("$0$1", &["a", "b"]));
assert_eq!("$1b", example("$0$1", &["$1", "b"]));
assert_eq!("moo", example("moo", &[]));
assert_eq!("abc", example("a$0b$0c", &[""]));
}
See also:
Upvotes: 2