Reputation: 151
Right now, all my images are basically inserted onto my page at the same time (or so it appears). How can I create an order, so my images appear one being one left, left to right, top to bottom?
I'm using MySQL to store the image name by the way. So maybe I should create an order by ascending ID for which the image name is processed onto my php? I don't know, any recommendations would be appreciated.
This is a small bit of the code to illustrate what I mean. It's the image code being looped:
echo '<img src="https://s3.amazonaws.com/pictures/' . $objResult["Image"] . '.png" />
EDIT: Here's the code for more context:
<html>
<body>
<?php
$objConnect = mysql_connect("localhost","root","") or die(mysql_error());
$objDB = mysql_select_db("dfvdfv");
$strSQL = "SELECT * FROM images";
if (!isset($_GET['Page'])) $_GET['Page']='0';
$objQuery = mysql_query($strSQL);
$Num_Rows = mysql_num_rows($objQuery);
$Per_Page = 16; // Per Page
$Page = $_GET["Page"];
if(!$_GET["Page"])
{
$Page=1;
}
$Prev_Page = $Page-1;
$Next_Page = $Page+1;
$Page_Start = (($Per_Page*$Page)-$Per_Page);
if($Num_Rows<=$Per_Page)
{
$Num_Pages =1;
}
else if(($Num_Rows % $Per_Page)==0)
{
$Num_Pages =($Num_Rows/$Per_Page) ;
}
else
{
$Num_Pages =($Num_Rows/$Per_Page)+1;
$Num_Pages = (int)$Num_Pages;
}
$strSQL .=" order by ImagesID ASC LIMIT $Page_Start , $Per_Page";
$objQuery = mysql_query($strSQL);
$cell = 0;
echo '<table border="1" cellpadding="2" cellspacing="1"><tr>';
while($objResult = mysql_fetch_array($objQuery))
{
if($cell % 4 == 0) {
echo '</tr><tr>';
}
if($cell == 2) {
echo '<td>RESERVED</td>';
} elseif ($cell == 3) {
echo '<td>The other cell</td>';
} else {
echo '
<td><img src="https://s3.amazonaws.com/images/' . $objResult["Image"] . '" />' .
$objResult["ImagesName"] . '</td>'; }
$cell++;
}
echo '</tr></table>';
?>
<br />
view more:
<?php
if($Prev_Page)
{
echo " <a href='$_SERVER[SCRIPT_NAME]?Page=$Prev_Page'>prev</a> ";
}
{
echo "|";
}
if($Page!=$Num_Pages)
{
echo " <a href ='$_SERVER[SCRIPT_NAME]?Page=$Next_Page'>next</a> ";
}
?>
<?php
mysql_close($objConnect);
?>
</body>
</html>
Upvotes: 0
Views: 181
Reputation: 47241
Assuming your iterating through a single loop to write your html and therefor the images it could be easily done by setting the css float attribute to left, put the images in a div container with a size of your choice, so the images row will break if they reach the right border. This will lead to building up the images from left to right.
A code example with your snippet embedded:
// open container
echo '<div style="width:\'500px\'">';
foreach ($results as $key => $objResult) {
echo '<img style="float:left;" src="https://s3.amazonaws.com/pictures/' . $objResult["Picture"] . '.png" />';
}
// close container
echo '</div>';
I suggest using stylesheet instead of setting the style attribute directly but for simplicity of the example it's just this way.
example for second question in comments
if ($objResult["description"]) {
$imageTitle = $objResult["description"];
} else {
$imageTitle = $objResult["number"];
}
echo
'<td>'.
'<img src="https://s3.amazonaws.com/images/' . $objResult["Image"] . '" />' .
$imageTitle .
'</td>';
Upvotes: 2
Reputation: 21466
If you want to change the order in which images appear, add a sort_order column to your database and put an index on it. When you add pictures, increment the sort_order. I prefer to increment by 10 so I have room to move images in-between others.
When you select from the database make sure you ORDER BY sort_order
.
Upvotes: 1