CODEWITHSUNDEEP
phpstring
user1264
user1264

Reputation: 61

Using str_word_count to count letters within the opponent word

user 1 writes a word (word1) and I want to count how many letters of the word1 there are within the opponent word (word2). At first I used the strpos function but it doesn't seem to count reppeated letters so I change to the str_word_count function but no matter what the word1 is the countex is always 5 This is my code:

 for($i=0;$i<10 && ($rowword=mysqli_fetch_assoc($result)) ;$i++){

    $aword1 = str_split($rowword['word']);
     $word2=$row['word2']; //$row comes from another query that gets the word of the opponent
     $countex=0;

        for($i=0;$i<5;$i++){
            $currentletter=$aword1[$i];

            if(str_word_count($word2,0,$currentletter)){
                $countex++;
            }    
        }

 } //end of outter for

Can someone tell me what is the problem?

Example of what I want to achieve:

word2=annoy, word1=again in this example countex should be 2 because in the word "again" the letter "a" and "n" exist in the word "annoy"

Upvotes: 0

Views: 49

Answers (2)

xate
xate

Reputation: 6379

You can use str_split aswell as strpos for that:

https://3v4l.org/7ogrE

<?php

$word1 = 'abcdefghijkl';
$word2 = 'acgikluuo';
$expected = 6;

function countMatchingChars($word1, $word2) {
    $matching = 0;
    foreach(str_split($word1) as $char) {
        if(strpos($word2, $char) !== false) {
            $matching++;
        }
    }

    return $matching;
}

$matchingChars = countMatchingChars($word1, $word2);

assert($matchingChars === $expected);

References:

http://php.net/str_split

http://php.net/strpos

Upvotes: 0

JohnnyB1988
JohnnyB1988

Reputation: 178

If you want to know how many letters are in both words then you can use this code:

$lettersFromWord1 = str_split ($word1);
$lettersFromWord2 = str_split ($word2);

$matches  = 0;
foreach($lettersFromWord1 as $letter){
    if ( in_array($letter, $lettersFromWord2)){
        $matches++;
    }
}

echo "Word: " . $word1 . " and Word: " . $word2 . " has " . $matches . " matching letters";

Upvotes: 1

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