Reputation: 3498
I am trying to pass a Series number in a Google Chart option through a variable. However it is not accepting it as a variable and instead is taking it as a string. You can see in Image1 that I have passed in Series parameter SecondseriesColumnNumber as a variable and value is 1.
However in the output it is considering it as a string but not as the series number as shown below
Image 2
Other parameters are considering the values correctly but not the series one. How can I make this work? My code is below
var options = {
title: title,
width: width,
height: height,
bar: { groupWidth: '75%' },
chartArea: { left: "8%", right: "8%", top: "10%", width: "100%", height: "75%" },
backgroundColor: 'transparent',
tooltip: { textStyle: { color: 'black' }, isHtml: true },
isStacked: isStacked,
seriesType: seriesType,
series: { SecondseriesColumnNumber: { type: SecondseriesType } },
hAxis: { slantedText: true }
};
var chart = new google.visualization.ComboChart($('DivSeries')[0]);
Upvotes: 0
Views: 1225
Reputation: 61212
the problem has to do with JavaScript syntax.
you are not able to use a variable as a key in the definition of an object.
you must first create the object, then you can add additional keys using variables.
there are two ways to get / set values of object keys, once the object is defined.
both of the following will return the same value for title.
var title = options.title;
var title = options['title'];
where as in the latter, we can substitute a variable for the title key.
var key = 'title';
var title = options[key];
in this case, define the static options as needed.
var options = {
title: title,
width: width,
height: height,
bar: { groupWidth: '75%' },
chartArea: { left: "8%", right: "8%", top: "10%", width: "100%", height: "75%" },
backgroundColor: 'transparent',
tooltip: { textStyle: { color: 'black' }, isHtml: true },
isStacked: isStacked,
seriesType: seriesType,
series: {},
hAxis: { slantedText: true }
};
then you can use a variable to further define the series option.
var SecondseriesColumnNumber = 1;
options.series[SecondseriesColumnNumber] = { type: SecondseriesType };
Upvotes: 2