CODEWITHSUNDEEP
mysqlsqlphpmyadmin
Nasser Hajlawi
Nasser Hajlawi

Reputation: 311

mysql query showing wrong result

I have a database table look like this

+======+===========+============+
|  ID  | user Name |user surname|
+======+===========+============+
| 100  |  name     |  surname   |
| 101  |  name     |  surname   |
| 102  |  name     |  surname   |
+===============================+

When i run this query which should show me no rows because there is no row with 101foo2 value :

SELECT * FROM tableName WHERE ID = '101foo2'

I am getting a result with same ID without the foo2 word

+======+===========+============+
|  ID  | user Name |user surname|
+======+===========+============+
| 101  |  name     |  surname   |
+===============================+

how it is showing the row with ID 101 if my query is ID = '101foo2'

Upvotes: 2

Views: 1234

Answers (1)

Gordon Linoff
Gordon Linoff

Reputation: 1270391

You are mixing types. ID is an integer (or number). You are comparing it to a string. So, MySQL needs to decide what type to use for the comparison. What types gets used? Well, a string? No. A number. The string is converted to a number, using the leading digits. So, it becomes 101 and matches.

You should really only compare numbers to numbers, and strings to strings. You could try to write the code as:

SELECT * FROM tableName WHERE ID = 101foo2

However, you would get an error. Another possibility is to force the conversion to a string:

SELECT * FROM tableName WHERE CAST(ID as CHAR) = '101foo2'

Upvotes: 4

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