Reputation: 13
I am looking to count the number of times set of values occurred in a table. These values could occur in up to 10 different columns. I need to increment the count regardless of which column it is in. I know how I could count if they were all in the same column but not spanning multiple columns.
Values can be added in any order. I have about a thousand
Cpt1 Cpt2 Cpt3 Cpt4 Cpt5
63047 63048 63048 NULL NULL
I would want to for this row I'd expect this as the result
63047 1
63048 2
Upvotes: 1
Views: 174
Reputation: 1271231
Many databases support lateral joins, of one type of another. These can be used to simplify this operation. Using the SQL Server/Oracle 12C syntax:
select v.cpt, count(*)
from t cross apply
(values (cpt1), (cpt2), . . .
) v(cpt)
where cpt is not null
group by v.cpt;
Upvotes: 0
Reputation: 37718
Something like this might work (after adapting to your value domain and data types):
create table t1
(i1 int,
i2 int,
i3 int);
insert into t1 values (1,0,0);
insert into t1 values (1,1,1);
insert into t1 values (1,0,0);
declare @i int = 0;
select @i = @i + i1 + i2 + i3 from t1;
print @i;
drop table t1;
Output is: 5
Upvotes: 0
Reputation: 6002
It's not entirely clear what your table exactly looks like, but I'm guessing that what you're looking for is:
SELECT row_count = COUNT(*),
row_count_with_given_value = SUM ( CASE WHEN field1 = 'myValue' THEN 1
WHEN field2 = 'myValue' THEN 1
WHEN field3 = 'myValue' THEN 1
WHEN field4 = 'myValue' THEN 1 ELSE 0 END)
FROM myTable
Assuming the fieldx
columns are not NULL-able, you could write it like this too:
SELECT row_count = COUNT(*),
row_count_with_given_value = SUM ( CASE WHEN 'myValue' IN (field1, field2, field3, field4) THEN 1 ELSE 0 END)
FROM myTable
Upvotes: 0
Reputation: 312404
You could use a union all
call to treat them as one column:
SELECT col, COUNT(*)
FROM (SELECT col1 FROM mytable
UNION ALL
SELECT col2 FROM mytable
UNION ALL
SELECT col3 FROM mytable
-- etc...
) t
GROUP BY col
Upvotes: 1