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c++operator-overloadingnew-operator
user673114
user673114

Reputation:

Overloading operator new for a class

When we overload new operator of a class, we declare the function as a member function. For eg:

class OpNew {
public:
    OpNew() { cout << "OpNew::OpNew()" << endl;}
    void* operator new(size_t sz) {
         cout << "OpNew::new: "
            << sz << " bytes" << endl;
         return ::new char[sz];
    }
};

How does the statement OpNew *obj = new OpNew work under the hood ? as overloaded new is a member of OpNew class not a static. So how does compiler ensure this call to new member function succeeds?

Upvotes: 25

Views: 13916

Answers (1)

Ben Voigt
Ben Voigt

Reputation: 283624

An operator new() or operator new[]() for a class is always a static class member, even if it is not declared with the keyword static.

What the C++ standard says (draft n3242), in section [class.free]:

Any allocation function for a class T is a static member (even if not explicitly declared static).

Upvotes: 37

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