CODEWITHSUNDEEP
regexpcreregex-lookarounds
dorony
dorony

Reputation: 1072

Regex: don't match if the pattern start with /

My regex (PCRE): 

\b([\w-.]*error)\b(?:[^-\/.]|\.\W|\.$|$)

is a match (the actual match is surrounded by stars) : 

**this.is.an.error**  
**this.IsAnerror**  
**this.is.an.error**.  
**this.is.an.error**(  
bla **this_is-an-error**  
**this.is.an.error**:  
this is an (**error**)

not a match: 

this.is.an.error.but.dont.match  
this.is.an.error-but.dont.match  
this.is.an.error/but.dont.match  
this.is.an.error/  
/this.is.an.error

for this sample: /this.is.an.error I can't manage to have a condition that will reject the whole match if it starts with the character /. every combination I've tried resulted in some partial catch (which is not the desired).

Is there any simple or fancy way to do that?

Upvotes: 2

Views: 200

Answers (2)

mrzasa
mrzasa

Reputation: 23307

You can try to add lookabehinds at the beginning instead of a word boundary:

(?<!\/)(?<=[^\w-.])([\w-.]*error)\b(?:[^-\/.]|\.\W|\.$|$)

Explanation:

  • (?<!\/) - negative lookbehind assuring there is no / before the first character;
  • (?<=[^\w-.]) - word boundary implementation taking into account your extended definition of characters accepted for a word [\w-.];

Demo

Upvotes: 1

revo
revo

Reputation: 48711

Prepend your regex with \/.*|:

\/.*|\b([\w-.]*error)\b(?=[^-\/.]|(?:\.\W?)?$)

Now just like before the first capturing group holds the desired part.

See live demo here

Note: I made some modifications to your regex to remove unnecessary alternations.

Upvotes: 1

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