CODEWITHSUNDEEP
laravel
wwwrrrxxx
wwwrrrxxx

Reputation: 195

laravel pass select option value to form action parameter

I am making a page with select option. If I select one option and click a button. It will go to that page with parameter in url.

I want to know is there any easy way to insert categoryId as parameter into action? 

<form method="GET" action="{{ route('routename', ['categoryId' => 1]) }}">
@foreach($categories as $category)
<select>
    <option value="1">{{ $category->name }}</option>
    <option value="2">{{ $category->name }}</option>
    <option value="3">{{ $category->name }}</option>
</select>
@endforeach

<button>Change</button>

</form>

Upvotes: 0

Views: 3950

Answers (1)

Petay87
Petay87

Reputation: 1773

You are being too specific in your route

You should remove the categoryId from the route. Instead you should point your route to a controller that just accepts a Request. then you can read the value of the select box in the controller and direct the user to the view depending on the selected option.

Your view:

<form method="GET" action="{{ route('routename') }}">
@csrf
<select name='selectOption'>
@foreach($categories as $category)
    <option value="{{ $category->id }}">{{ $category->name }}</option>
</select>
@endforeach

<button>Change</button>

</form>

Your Route:

Route::get('url', 'Controller@functionName')->name('routename');

Your Controller:

use Illuminate\Http\Request;
public function functionName(Request $request)
{

  $option = $request->selectOption;

  if($option == 1){
    CODE FOR OPTION 1 HERE
  }
}

This way the route will not require the parameter to be defined in the URL. Instead you can pass it as a parameter in the request to be read in the controller. You could then have a if rule for each option that then returns a different view.

Upvotes: 2

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