Set a variable if undefined in JavaScript

Question

I know that I can test for a JavaScript variable and then define it if it is undefined, but is there not some way of saying

var setVariable = localStorage.getItem('value') || 0;

seems like a much clearer way, and I'm pretty sure I've seen this in other languages.

Answer 1

Logical nullish assignment, ES2021+ solution

New operators are currently being added to the browsers, ??=, ||=, and &&=. This post will focus on ??=.

This checks if left side is undefined or null, short-circuiting if already defined. If not, the right-side is assigned to the left-side variable.

Comparing Methods

// Using ??=
name ??= "Dave"

// Previously, ES2020
name = name ?? "Dave"

// or
if (typeof name === "undefined" || name === null) {
    name = true
}

// Before that (not equivalent, but commonly used)
name = name || "Dave" // Now: name ||= "Dave"

Basic Examples

let a       // undefined
let b = null
let c = false

a ??= true  // true
b ??= true  // true
c ??= true  // false

Object/Array Examples

let x = ["foo"]
let y = { foo: "fizz" }

x[0] ??= "bar"  // "foo"
x[1] ??= "bar"  // "bar"

y.foo ??= "buzz"  // "fizz"
y.bar ??= "buzz"  // "buzz"

x  // Array [ "foo", "bar" ]
y  // Object { foo: "fizz", bar: "buzz" }

??= Browser Support Nov 2024 - 95%

??= Mozilla Documentation

||= Mozilla Documentation

&&= Mozilla Documentation

Answer 2

It seems to me, that for current javascript implementations,

var [result='default']=[possiblyUndefinedValue]

is a nice way to do this (using object deconstruction).

As noted on mdn, in this case the default value really is only used if the value is undefined, not if it is merely falsy or null.

Answer 3

You can use any of below ways.

let x;
let y = 4;
x || (x = y)

in ES12 or after

let x;
let y = 4;
x ||= y;

Answer 4

ES2020 Answer

With the Nullish Coalescing Operator, you can set a default value if value is null or undefined.

const setVariable = localStorage.getItem('value') ?? 0;

However, you should be aware that the nullish coalescing operator does not return the default value for other types of falsy value such as 0 and ''.

However, do take note of the browser support. You may need to use a JavaScript compiler like Babel to convert it into something more backward compatible. If you are using Node.js, it has been supported since version 14.

Answer 5

In our days you actually can do your approach with JS:

// Your variable is null
// or '', 0, false, undefined
let x = null;

// Set default value
x = x || 'default value';

console.log(x); // default value

So your example WILL work:

const setVariable = localStorage.getItem('value') || 0;

Answer 6

If you're a FP (functional programming) fan, Ramda has a neat helper function for this called defaultTo :

usage:

const result = defaultTo(30)(value)

It's more useful when dealing with undefined boolean values:

const result2 = defaultTo(false)(dashboard.someValue)

Answer 7

Yes, it can do that, but strictly speaking that will assign the default value if the retrieved value is falsey, as opposed to truly undefined. It would therefore not only match undefined but also null, false, 0, NaN, "" (but not "0").

If you want to set to default only if the variable is strictly undefined then the safest way is to write:

var x = (typeof x === 'undefined') ? your_default_value : x;

On newer browsers it's actually safe to write:

var x = (x === undefined) ? your_default_value : x;

but be aware that it is possible to subvert this on older browsers where it was permitted to declare a variable named undefined that has a defined value, causing the test to fail.

Answer 8

Works even if the default value is a boolean value:

var setVariable = ( (b = 0) => b )( localStorage.getItem('value') );

Answer 9

The 2018 ES6 answer is:

return Object.is(x, undefined) ? y : x;

If variable x is undefined, return variable y... otherwise if variable x is defined, return variable x.

Answer 10

I needed to "set a variable if undefined" in several places. I created a function using @Alnitak answer. Hopefully it helps someone.

function setDefaultVal(value, defaultValue){
   return (value === undefined) ? defaultValue : value;
}  

Usage:

hasPoints = setDefaultVal(this.hasPoints, true);

Answer 11

It seems more logical to check typeof instead of undefined? I assume you expect a number as you set the var to 0 when undefined:

var getVariable = localStorage.getItem('value');
var setVariable = (typeof getVariable == 'number') ? getVariable : 0;

In this case if getVariable is not a number (string, object, whatever), setVariable is set to 0

Answer 12

Ran into this scenario today as well where I didn't want zero to be overwritten for several values. We have a file with some common utility methods for scenarios like this. Here's what I added to handle the scenario and be flexible.

function getIfNotSet(value, newValue, overwriteNull, overwriteZero) {
    if (typeof (value) === 'undefined') {
        return newValue;
    } else if (value === null && overwriteNull === true) {
        return newValue;
    } else if (value === 0 && overwriteZero === true) {
        return newValue;
    } else {
        return value;
    }
}

It can then be called with the last two parameters being optional if I want to only set for undefined values or also overwrite null or 0 values. Here's an example of a call to it that will set the ID to -1 if the ID is undefined or null, but wont overwrite a 0 value.

data.ID = Util.getIfNotSet(data.ID, -1, true);

Answer 13

var setVariable = (typeof localStorage.getItem('value') !== 'undefined' && localStorage.getItem('value')) || 0;