CODEWITHSUNDEEP
pythonpython-3.xstring
demmybite
demmybite

Reputation: 51

Print each word in string using index slicing

I want to print each word in word = "They stumble who run fast" on a new line using index slicing.

I've tried using a while loop, like printing words after each space

word = "They stumble who run fast"
space = word.count(' ')
start = 0
while space != -1:
   print(word[start:space])

The result should be like this:

They
stumble
who
run
fast

Upvotes: 2

Views: 6689

Answers (6)

Alistair Jarratt
Alistair Jarratt

Reputation: 1

Let's try not to overthink this.

If you don't need to index slicing and then just do:

word = "They stumble who run fast"
print (word.replace(" ", '\n'))

Upvotes: 0

Josh Voyles
Josh Voyles

Reputation: 21

Posting another way if a student needs an example and must do index slicing.

    check = 0 # Here we start slicing at zero
    
    split = 0
    
    for x in word:
        if x == ' ':  # Will check for spaces
            print(word[check:split])
            check = split + 1  # check will inherit splits value plus one when space found
        split = split + 1  # spit will increase each time no space is found
    print(word[check:split])  # needed to print final word

Upvotes: 1

lee_f
lee_f

Reputation: 11

I think I know what this problem is for (edx class..as I ran into the same thing). This solution worked for me using the pieces they're encouraging the students to use at this point in the course:

quote = "they stumble who run fast"
start = 0
space_index = quote.find(" ")
while space_index != -1:
    print (quote[start:space_index])
    start = space_index+1
    space_index = quote.find(" ", space_index+1)
else:
    print (quote[start::1])

Upvotes: 1

benvc
benvc

Reputation: 15120

Not sure why anyone would want to do this rather than just use str.split(), but here is another (fairly ugly) way along the lines of your initial stab at it.

word = "They stumble who run fast"
while ' ' in word:
    i = word.index(' ')
    print(word[:i])
    word = word[i+1:]
print(word)

# OUTPUT
# They
# stumble
# who
# run
# fast

Upvotes: 0

Mad Physicist
Mad Physicist

Reputation: 114300

The obvious solution would be to use str.split, but that would violate your desire for slicing:

for w in word.split():
    print(w)

A better way might be to keep track of an index for the current space and keep looking for the next one. This is probably similar to what you had in mind, but your loop doesn't update and variables:

start = 0
try:
    while True:
        end = word.index(' ', start)
        print(word[start:end])
        start = end + 1
except ValueError:
    print(word[start:])

A shortcut that probably won't be acceptable either, but produces the desired output:

print(word.replace(' ', '\n'))

Upvotes: 0

iz_
iz_

Reputation: 16593

If you absolutely need to use index slicing:

word = "They stumble who run fast"

indexes = [i for i, char in enumerate(word) if char == ' ']

for i1, i2 in zip([None] + indexes, indexes + [None]):
    print(word[i1:i2].strip())

Output:

They
stumble
who
run
fast

But why not use .split()?

word = "They stumble who run fast"
print(*word.split(), sep='\n')

Output:

They
stumble
who
run
fast

Upvotes: 4

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