Reputation: 1151
I have an empty list my_list=[]
and I want to iteratively add arrays to this list. Suppose my arrays are [1,2,3]
, [4,5,6]
, [7,8,9]
,[10,11,12]
, I want to have a list such that my_list=[[1,2,3], [4,5,6], [7,8,9], [10,11,12]]
such that each element of the list is an array.
Upvotes: 0
Views: 315
Reputation: 39052
Just use append
. Sample example assuming you have four variables storing the arrays/lists to add to the list
my_list=[]
a = [1,2,3]
b = [4,5,6]
c = [7,8,9]
d = [10,11,12]
my_list.append(a)
my_list.append(b)
my_list.append(c)
my_list.append(d)
# [[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12]]
If you want some iterative solution, use the following list comprehension way. Although here finally my_list
and arrays
are the same.
arrays = [[1,2,3], [4,5,6], [7,8,9], [10,11,12]]
my_list = [i for i in arrays]
If you don't prefer list comprehension
my_list = []
for i in arrays:
my_list.append(i)
NumPy way : One of the possible solutions using append
arrays = np.array([[1,2,3], [4,5,6], [7,8,9], [10,11,12]])
my_list = np.empty((0,len(arrays[0])))
for arr in arrays:
my_list = np.append(my_list, [arr], axis=0)
Another way using vstack
where 3 in (0,3)
correspond to the number of columns (length of a single list).
my_list = np.array([]).reshape(0,3)
for arr in arrays:
my_list = np.vstack((my_list, arr))
Upvotes: 2