CODEWITHSUNDEEP
sqlsql-serverstringt-sqlsql-like
Anand KC
Anand KC

Reputation: 39

SQL: Combining LIKE and IN in SQL , and Showing the Array of LIKE in a column

Below code works to combine Like and IN. But I need a column in the output with the values that I used for the Like:

SELECT file_id
FROM   table1 as t
WHERE  archival_date = '20180108'
WHERE  EXISTS(SELECT *
              FROM   (VALUES ('%portfolo1filename%'),
                             ('%portfolo2filename%'),
                             ('%portfolo3filename%')) Vals(val)
              WHERE  filename LIKE '%' + val + '%')

What I need as Output:

____________________________
val                  file_ID
____________________________
portfolo1filename     2230
portfolo2filename     2240
portfolo3filename     3345

Current code's Output:

______________
   file_ID
______________
     2230
     2240
     3345

Note: val here contains the list of values (i.e filenames) that I need to search as like

table1 has following entries:

filename                             file_ID    archival_date 
__________________________________________________________________
Broker1_portfolo1filename             2230         20180108
Broker1_portfolo2filename             2240         20180108
Broker2_portfolo3filename             3345         20180908
Broker2_portfolo2filename             1345         20180904
Broker3_portfolo1filename             3045         20180906
Broker2_portfolo2filename             3355         20180907
Broker2_portfolo3filename             7340         20180901

Upvotes: 1

Views: 107

Answers (2)

Derviş Kayımbaşıoğlu
Derviş Kayımbaşıoğlu

Reputation: 30665

this might help,

select  distinct file_id, val
from table1,  VALUES ('%portfolo1filename%'),
                     ('%portfolo2filename%'),
                     ('%portfolo3filename%')) Vals(val)
where column1 like '%' + val + '%'

working code You can check yourself

CREATE TABLE [dbo].[table1](
    [id] [int] NULL,
    [column1] [varchar](40) NULL
) ON [PRIMARY]
GO

insert into table1 values (2230,    'portfolo1filename');
insert into table1 values (2245,    'portfolo2filenamedasdas');
insert into table1 values (2250,    'porto');


select  distinct id, val
from table1, (VALUES ('%portfolo1filename%'),
                     ('%portfolo2filename%'),
                     ('%portfolo3filename%')) Vals(val)
where column1 like '%' + val + '%'

Working Fiddle

Upvotes: 0

GMB
GMB

Reputation: 222672

One solution would be to convert your WHERE EXISTS clause to an INNER JOIN, like :

SELECT t1.file_id, vals.val
FROM
    table1 t1
    INNER JOIN  (VALUES ('value1'), ('value2'), ('value3')) Vals(val) 
        ON  t1.column1 LIKE '%' + vals.val + '%'

The downside of this approach is that if multiple expression match the value of column1 in a given record, you will find two rows in the output. To avoid that, you could for example concatenate all succesfully matched expressions in a single field.

If you are using SQL Server 2017 (your query runs fine on this RDBMS), you can use STRING_AGG :

SELECT t1.file_id, STRING_AGG(vals.val, ',')
FROM   
    table1 t1
    INNER JOIN  (VALUES ('value1'), ('value2'), ('value3')) Vals(val) 
        ON  t1.column1 LIKE '%' + vals.val + '%' 
GROUP BY t1.file_id

Tested in this db fiddle.

Upvotes: 1

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