Reputation: 52366
I am having trouble figuring out how to pass a parameter to a query. In this case, I want to get a user by name field. I know I can pass an id, but how do I pass another field? Do I need to create a secondary index?
private AWSAppSyncClient mAWSAppSyncClient;
mAWSAppSyncClient.query(GetUserQuery.builder().build())
.responseFetcher(AppSyncResponseFetchers.CACHE_AND_NETWORK)
.enqueue(userCallback);
query GetUser($id: ID!) {
getUser(id: $id) {
id
userId
name
...
}
}
Upvotes: 1
Views: 1009
Reputation: 52366
Use ListUsers (ListXXXX) to query with multiple parameters.
Example - query by name = "aaa":
ModelStringFilterInput modelStringFilterInput = ModelStringFilterInput.builder().eq("aaa").build();
ModelUserFilterInput modelUserFilterInput = ModelUserFilterInput.builder().name(modelStringFilterInput).build();
mAWSAppSyncClient.query(ListUsersQuery.builder().filter(modelUserFilterInput).build())
.responseFetcher(AppSyncResponseFetchers.CACHE_AND_NETWORK)
.enqueue(userCallback);
private GraphQLCall.Callback<ListUsersQuery.Data> userCallback = new GraphQLCall.Callback<ListUsersQuery.Data>() {
@Override
public void onResponse(@Nonnull Response<ListUsersQuery.Data> response) {
Log.d(TAG, response.data().listUsers().items().toString());
}
@Override
public void onFailure(@Nonnull ApolloException e) {
Log.d(TAG, e.toString());
}
};
Upvotes: 1