CODEWITHSUNDEEP
javascriptarraystypescript
Sebastian
Sebastian

Reputation: 63

How can I check in a array of objects if one of the objects contain just a part of a string?

How can I check in a array of objects if one of the objects contain just a part of a string ?

products = [
{id: 'pdc', code: '123456', name: 'pompa'},
{id: 'kbr', code: '2365', name: 'kit kbr'},
{id: 'boiler', code: '23165', name: 'VPB'}
];

And let's say I want to find if the this.products contain an object with 'kbr' ? And, as you can see, that object has a longer name.. Something like:

const matches = this.products.filter(s => s.includes('kbr'));

Thank you!

Upvotes: 0

Views: 79

Answers (8)

Mario Proietti
Mario Proietti

Reputation: 182

In the filter function, you didn't specified the field to be checked. So you've to write this if you want to check on name property:

const matches = this.products.filter(s => s.name.includes('kbr'));

Upvotes: 1

mgabor6
mgabor6

Reputation: 541

I would use Array.find() function, because it stops at the first matching object:

const products = [
    {id: 'pdc', code: '123456', name: 'pompa'},
    {id: 'kbr', code: '2365', name: 'kit kbr'},
    {id: 'boiler', code: '23165', name: 'VPB'}
];

const testPattern = 'kbr';

const productsContains = (products, pattern) => 
    products.find(
      ({id, name}) => 
          id.indexOf(pattern) >= 0 || name.indexOf(pattern) >= 0
      ) ? true : false;

console.log(`productsContains '${testPattern}':`, productsContains(products, testPattern));

It isn't working in IE, but there is polyfill.

Upvotes: 0

Prince Hernandez
Prince Hernandez

Reputation: 3731

using some is a better approach for this, it will stop as soon as it founds something. for larger arrays it will be an improvement :)

products = [
{id: 'pdc', code: '123456', name: 'pompa'},
{id: 'kbr', code: '2365', name: 'kit kbr'},
{id: 'boiler', code: '23165', name: 'VPB'}
];

const result = products.some(product => Object.keys(product).some(key => product[key].includes('kbr')))
console.log(result)

Upvotes: 1

Shidersz
Shidersz

Reputation: 17190

You can generate the array of the Object.values() inside the filter method and check if some of the values match() the string you are searching for:

const products = [
    {id: 'pdc', code: '123456', name: 'pompa'},
    {id: 'kbr', code: '2365', name: 'kit kbr'},
    {id: 'boiler', code: '23165', name: 'VPB'}
];

let res = products.filter(o =>
{
    return Object.values(o).some(x => ("" + x).match("kbr"));
});

console.log(res);

Upvotes: 0

Taki
Taki

Reputation: 17654

you can stringify the object values and see if it has the substring you're looking for :

const products = [{ id: 'pdc', code: '123456', name: 'pompa' }, { id: 'kbr', code: '2365', name: 'kit kbr' }, { id: 'boiler', code: '23165', name: 'VPB' }];

const result = products.filter(prod =>
  Object.values(prod).join(' ').includes('kbr'));

console.log(result)

Upvotes: 0

kockburn
kockburn

Reputation: 17636

You were almost there. You simply needed to access the "name" property of your object "s". In this scenario I used destructuring to get quick access to "name" property.

const products=[{id:"pdc",code:"123456",name:"pompa"},{id:"kbr",code:"2365",name:"kit kbr"},{id:"boiler",code:"23165",name:"VPB"}];

const res = products.filter(({name})=>name.includes("kbr"));

console.log(res);

Upvotes: 1

Jonas Wilms
Jonas Wilms

Reputation: 138477

You could compose all values to a string and check if it includes that:

 const matches = this.products.filter(s => Object.values(s).join("¥").includes('kbr'));

Upvotes: 0

Nina Scholz
Nina Scholz

Reputation: 386756

You need the values of the object and then iterate until a match is found.

var products = [{ id: 'pdc', code: '123456', name: 'pompa' }, { id: 'kbr', code: '2365', name: 'kit kbr' }, { id: 'boiler', code: '23165', name: 'VPB' }],
    matches = this.products.filter(o => 
        Object.values(o).some(v => v.toString().includes('kbr'))); 
 
console.log(matches);

Upvotes: 1

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