CODEWITHSUNDEEP
ruby
Dennis
Dennis

Reputation: 1975

Check for inclusion of a hash against another hash

I have an array of hashes like this:

arr = [
  { email: '[email protected]', valid: true },
  { email: '[email protected]', valid: false }
]

I need to check if email: '[email protected]' and valid: true both exist in a single hash.

How can I check for such hash in the array without using each loop?

Currently I am doing this:

found = false
arr.each do|v|
  if v[:email] == '[email protected]' && v[:valid] == true
    found = true
    break
  end
end

Upvotes: 3

Views: 289

Answers (2)

sawa
sawa

Reputation: 168131

To check if a hash has all the key-value pairs that another hash has, use >, <, or their variants >=, <=. You can be assured that the order of key-value pairs does not matter.

arr.any?{|h| h >= {email: "[email protected]", valid: true}}
# => true

arr.any?{|h| h >= {valid: true, email: "[email protected]"}}
# => true

Upvotes: 7

mrzasa
mrzasa

Reputation: 23327

You can use Enumerable#any? that does more or less what you did in your implementation:

> found = arr.any?{|e| e[:email] == '[email protected]' && e[:valid] }
=> true

Upvotes: 7

Related Questions