CODEWITHSUNDEEP
php
Mr. Jo
Mr. Jo

Reputation: 5251

PHP: Generate unique random int number based on an id

I'm currently searching for a good way to generate a unique random number for SEPA transactions (End-to-End reference) with 27 digits in PHP. My requirements are:

I've tried this solution here but this only gives me a string with letters and numbers:

md5( uniqid( mt_rand(), true ) );

Does anyone has a lightweight solution or idea?

Upvotes: 1

Views: 2570

Answers (3)

dasun
dasun

Reputation: 41

To get a 27-digit integer, you can take the first 27 characters of the hexadecimal hash and convert it to an integer.

try this:

function generateUniqueRandomInt($userId) {
    $uniqueString = $userId . uniqid('', true); // Concatenate user ID and unique ID
    $hashedString = hash('sha256', $uniqueString); // Generate SHA-256 hash
    $first27Digits = substr($hashedString, 0, 27); // Take the first 27 characters
    $uniqueNumber = (int) $first27Digits; // Convert to integer

    return str_pad($uniqueNumber, 27, '0', STR_PAD_LEFT); // Pad with leading zeros if needed
}

You can use this function to generate a unique random integer number with 27 digits:

$userID = 12345; // Replace with the actual user ID
$uniqueRandomNumber = generateUniqueRandomInt($userID);
echo $uniqueRandomNumber;

Upvotes: 0

Bira
Bira

Reputation: 5506

echo $bira = date('YmdHis').rand(1000000000000,9000000000000);
echo "<br/>";
echo strlen($bira);

Add the time stamp in the front, so it will be unique always.

OR echo $bira = time().rand(10000000000000000,90000000000000000);

outoput:

201901220142532979656312614

27

Upvotes: 4

Obsidian Age
Obsidian Age

Reputation: 42304

How about this:

$array = [];
$numberOfTransactions = 1;

while (count($array) < $numberOfTransactions) {
    $rand = mt_rand(100000000000000000000000000, 999999999999999999999999999);
    $array[$rand] = $rand;
}

print_r($array);

Associative array keys are unique, so you won't get any duplicates.

Upvotes: 1

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