CODEWITHSUNDEEP
google-apps-script
medic17
medic17

Reputation: 56

Deconstructing 2D array in Google Apps Script

I am trying to destructure a 2D array in Google Apps Script and it remains unchanged.

I found a link that explains how to destructure an array in google apps script similar to the syntax for javascript es6.

The link is https://plus.google.com/u/0/+DimuDesigns/posts/9FDJx2qe4gZ

The example they give works fine for me in as a separate function. 

function readData() {
  var id = '1P4aVeFJMT9e0ijoFt262IuLlnjHte8hl2iUeU_kk-AQ'; //ID of the 
projects spreadsheet
  var ass = SpreadsheetApp.openById(id); //Initilize spreadsheet
  var sheet = ass.getSheetByName('Sheet1'); //Get sheet instence

  var row1data = sheet.getRange('A1:F1').getValues();

  [a1, b1, c1, d1, e1, f1] = [row1data];  

  //DEBUG
  Logger.log(a1);
}

expected output to log should be the data in cell A1 which is the first item in the array.

actual output is the array itself.

I am a beginner in general so a clear explanation with well commented code would be appreciated.

Upvotes: 3

Views: 410

Answers (1)

Tanaike
Tanaike

Reputation: 201358

How about this modification? I think that there are 2 errors in your script.

  1. When the values of "a1","b1","c1","d1","e1" and "f1" are put in the cells of "A1:F1", row1data retrieved by var row1data = sheet.getRange('A1:F1').getValues() is like [["a1","b1","c1","d1","e1","f1"]]. This is 2 dimensional array.

  2. Variables of a1, b1, c1, d1, e1, f1 of [a1, b1, c1, d1, e1, f1] are required to be declared.

When above points are reflected to your script, it becomes as follows.

Modified script:

Please modify as follows.

From: 
[a1, b1, c1, d1, e1, f1] = [row1data];  

//DEBUG
Logger.log(a1);
To: 
var a1, b1, c1, d1, e1, f1;
[a1, b1, c1, d1, e1, f1] = row1data[0];

//DEBUG
Logger.log(a1);

Note:

  • Also you can use [[a1, b1, c1, d1, e1, f1]] = row1data instead of [a1, b1, c1, d1, e1, f1] = row1data[0].
  • As a sample, if [row1data] in your script is used, it becomes [[[a1, b1, c1, d1, e1, f1]]] = [row1data].

Reference:

Upvotes: 3

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