Hermann
Hermann

Reputation: 1

Unique array with member names

i have an array with group members (last_name, first_name), but in the group "Testgroup" is another group "Testgroup2". The bad thing is that i dont get unique values from both groups.

Can anyone help ? It´s Javascript

var manager_list = new Array;
var manager_list = new Array;
var srvData = new spl_srv();


    <LIST PREFIX=list WHERE="group.last_name = 'Testgroup'">
        var wc = "group = U'$list.member'";
        var data = srvData.read("grpmem", wc, "member.last_name|member.first_name|member");
        var anz  = srvData.getcount();
        if(anz > 0) {
            for (i=0; i<anz; i++){
                var UU_ID = srvData.getdata(i,2);
                UU_ID = UU_ID.replace(/\r?\n|\r/g,"");
                manager_list.push(srvData.getdata(i,0)+', '+srvData.getdata(i,1)+'@,@'+UU_ID);
            }
        } 
        else {

        manager_list.push("$list.member.last_name, $list.member.first_name@,@$list.member");
        }

Upvotes: 0

Views: 73

Answers (3)

Nilesh More
Nilesh More

Reputation: 61

One-liner simple and functional solution and it uses a standard and built-in function rather than a home-rolled solution.

var manager_list = ['smith', 'john', 'phil', 'john'];
var unique = manager_list.filter(function(item, i, arr){ return arr.indexOf(item) === i; });

// result = ['smith', 'john', 'phil'];

Upvotes: 0

Sudhir Sapkal
Sudhir Sapkal

Reputation: 1038

There are multiple ways to get Unique values from array(Removing duplicates)

  1. var uniqueManagers = []; $.each(manager_list, function(i, el){ if($.inArray(el, uniqueManagers) === -1) uniqueManagers.push(el); });

  2. let uniqueManagers = Array.from(new Set(manager_list))

Your code should be something like below

var manager_list = new Array;
var manager_list = new Array;
var srvData = new spl_srv();
       <LIST PREFIX=list WHERE="group.last_name = 'Testgroup'">
        var wc = "group = U'$list.member'";
        var data = srvData.read("grpmem", wc, "member.last_name|member.first_name|member");
        var anz  = srvData.getcount();
        if(anz > 0) {
            for (i=0; i<anz; i++){
                var UU_ID = srvData.getdata(i,2);
                UU_ID = UU_ID.replace(/\r?\n|\r/g,"");
                manager_list.push(srvData.getdata(i,0)+', '+srvData.getdata(i,1)+'@,@'+UU_ID);
            }
        } 
        else {

        manager_list.push("$list.member.last_name, $list.member.first_name@,@$list.member");
        }
  manager_list = Array.from(new Set(manager_list))

Upvotes: 3

slava_slava
slava_slava

Reputation: 666

I suppose you should flatten your array then filter:

const data = yourArray.reduce(
  (acc, current) => acc.concat(current), 
[]);
  
const uniqueItems = [...new Set(data)]; 

Upvotes: 0

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