CODEWITHSUNDEEP
ruby
user10773132
user10773132

Reputation:

Ruby array and loop

Ive been able to come up with one that is a completely solid star triangle but I'm having trouble creating a "hollow one" and a number one that both increments by whatever the number the user enters. Any help?

Upvotes: 2

Views: 172

Answers (5)

iGian
iGian

Reputation: 11183

Other options, just for fun.

Hollow

n, cat, hyp = 4, "šŸŽ±", "šŸŽ±"

n.times do |n|
  a = Array.new(n+1){' '}
  a[0], a[-1] = cat, hyp
  puts a.join
end

It returns:

# šŸŽ±
# šŸŽ±šŸŽ±
# šŸŽ± šŸŽ±
# šŸŽ±  šŸŽ±

Filled

n = 10
r = [*0..9, *'a'..'z']

n.times do |n|
  puts r[0..n].join
end

It returns

# 0
# 01
# 012
# 0123

If you shuffle the array r.shuffle[0..n].join, you could get random output:

# t
# 26
# ce0
# zqiw

Random emoji:

some_emotics = (0..9).each_with_object([]) { |n, o| o << "1F96#{n}".to_i(16) }.pack 'U*'
n.times do |n|
  puts some_emotics.split("").shuffle[0..n].join
end

to get:

# šŸ„”
# šŸ„¦šŸ„”
# šŸ„¤šŸ„„šŸ„ 
# šŸ„©šŸ„£šŸ„¦šŸ„„

Upvotes: 0

Cary Swoveland
Cary Swoveland

Reputation: 110665

def bt(n)
  1.upto(n) do |i|
    puts case i
    when 1
      '*'
    when n
      '*'*n
    else
      "*#{' '*(i-2)}*"
    end
  end
end

bt 8
*
**
* *
*  *
*   *
*    *
*     *
********


ROW = [*1..9, *'A'..'Z'].join
  #=> "123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ" 

def lt(n)
  1.upto(n) { |i| puts ROW[0,i] }
end

lt 8
1
12
123
1234
12345
123456
1234567
12345678


lt 22
1
12
123
1234
12345
123456
1234567
12345678
123456789
123456789A
123456789AB
123456789ABC
123456789ABCD
123456789ABCDE
123456789ABCDEF
123456789ABCDEFG
123456789ABCDEFGH
123456789ABCDEFGHI
123456789ABCDEFGHIJ
123456789ABCDEFGHIJK
123456789ABCDEFGHIJKL
123456789ABCDEFGHIJKLM


ROW = 'šŸ˜ˆ'*10
lt 6
šŸ˜ˆ
šŸ˜ˆšŸ˜ˆ
šŸ˜ˆšŸ˜ˆšŸ˜ˆ
šŸ˜ˆšŸ˜ˆšŸ˜ˆšŸ˜ˆ
šŸ˜ˆšŸ˜ˆšŸ˜ˆšŸ˜ˆšŸ˜ˆ
šŸ˜ˆšŸ˜ˆšŸ˜ˆšŸ˜ˆšŸ˜ˆšŸ˜ˆ

Upvotes: 1

Sash Sinha
Sash Sinha

Reputation: 22295

You could create a simple method with two loops, for the second triangle:

def print_numbers_right_triangle(height)
  1.upto(height) do |row|
    1.upto(row) do |i|
      print i
    end
    puts
  end
end

print "Plese enter the height of the triangle:"
print_numbers_right_triangle(gets.strip.to_i)

Example Usage:

Plese enter the height of the triangle: 8
1
12
123
1234
12345
123456
1234567
12345678

Upvotes: 0

Noctilucente
Noctilucente

Reputation: 356

This is my solution:

class RightTriangle
  class << self
    def draw_border(size:, char: '*')
      validate(size)

      1.upto(size) do |n|
        1.upto(n) do |o|
          break if n == size
          o == 1 || o == n ? print(char) : print(' ')
        end

        n.times { print char } if n == size

        puts if n > 0
      end
    end

    def draw_numbers(size:)
      validate(size)

      1.upto(size) do |n|
        1.upto(n) { |o| print o }
        puts
      end
    end

    private

    def validate(size)
      raise 'SizeError: `size` must be greater than 1' if size <= 1
    end
  end
end

# For the triangle border
RightTriangle.draw_border(size: 8) # character will be '*'
RightTriangle.draw_border(size: 8, char: 'a') # character will be 'a'

# For the numbers triangle
RightTriangle.draw_numbers(size: 8)

Upvotes: 1

Andre Figueiredo
Andre Figueiredo

Reputation: 13425

1st. iterate the lines

2nd. put "*" only in boundaries of the line: [0, i], filling " " inside:

3rd: exceptions for the 1st and last (n) case

n = 8

puts '*'

(n-2).times do |i|
  puts '*' + ' ' * (i) + '*'
end

puts '*' * n if n > 1

Upvotes: 1

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