CODEWITHSUNDEEP
pythonstring
Mohamed
Mohamed

Reputation: 57

Format the string with missing elements - Python

I have the following string:

string1 = "1/0/1/A1,A2"
string2 = "1/1/A1,A2"
string3 = "0/A1,A2"

In the above strings I have to replace the character with zero if it does not exist. The default structure will be "number/number/number/any_character`", if any of number is missing It has to replace with zero. The answer will be as follows.

print(string1) = "1/0/1/A1,A2"
print(string2) = "1/1/0/A1,A2"
print(string3) = "0/0/0/A1,A2"

Upvotes: 1

Views: 671

Answers (3)

Ajax1234
Ajax1234

Reputation: 71461

You can use str.split:

def pad_string(_input, _add='0'):
  *_vals, _str = _input.split('/')
  return '/'.join([*_vals, *([_add]*(3-len(_vals))), _str])

results = list(map(pad_string, ['1/0/1/A1,A2', '1/1/A1,A2', '0/A1,A2']))

Output:

['1/0/1/A1,A2', '1/1/0/A1,A2', '0/0/0/A1,A2']

Upvotes: 1

Ivo
Ivo

Reputation: 4200

If you want to use just string manipulation and loops, try this

strings_list = []
for string in [string1, string2, string3]:     # make list containing all strings
    strings_list.append(string)

new_strings = [] # make list containing the new strings
for string in strings_list:
    if string.count("0/") + string.count("1/") == 3:
        # identify the strings not missing a number
        new_strings.append(string)
    if string.count("0/") + string.count("1/") == 2:
        # identify the strings missing 1 number
        string = string[:4] + "0/" + string[4:]
        new_strings.append(string)
    if string.count("0/") + string.count("1/") == 1:
        # identify the strings missing 2 numbers
        string = string[:2] + "0/" + string[2:]
        new_strings.append(string)
print(new_strings)

This results in ['1/0/1/A1,A2', '1/1/0/A1,A2', '0/0/A1,A2'].

Upvotes: 0

Maurice Meyer
Maurice Meyer

Reputation: 18126

You can easily fill missing elements from the left:

def fillZeros(item):
    chunks = item.split('/')
    for inserts in range(0, 4 - len(chunks)):
        chunks.insert(0, '0')
    return '/'.join(chunks)

string1 = "1/0/1/A1,A2"
string2 = "1/1/A1,A2"
string3 = "0/A1,A2"


for myString in (string1, string2, string3):
    print fillZeros(myString)

Prints:

1/0/1/A1,A2
0/1/1/A1,A2
0/0/0/A1,A2

But for you string2 example you need to identify which element is missing: 1/1/A1,A2. Is the first or the third element missing ?!

Upvotes: 0

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