Reputation: 10992
Suppose the following line and cursor position:
foo = some_func(1 +[ ]2)
^^^
cursor position
Using di
+ (
I could easily get rid of everything inside the brackets or delete everything to line start or end using d^
and d$
respectively, but what would I do if I would like to delete everything that comes after =
?
The resulting line should be:
foo =[ ]
^^^
cursor position
dT
+=
deletes everything until (backwards) the character =
, but it still leaves 2)
in the line, ending up in:
foo =[2])
^^^
cursor position
I could, of course, jump to =
first and then use d$
to delete everything until line ending, but I would prefer a simple shortcut based on current cursor position without the need to move the cursor (if such a shortcut exists).
Upvotes: 1
Views: 373
Reputation: 198294
T=D (Jump to after =
, delete to end of line) is the shortest way, I believe.
You can do it without the movement first, but it is considerably more complex: :s/=\@<=.*//
CR
Upvotes: 2