CODEWITHSUNDEEP
javascript
Vencovsky
Vencovsky

Reputation: 31713

How to check if an object has keys that are in an array?

I have an array of strings and I want to check if the object has all properties that are in this array.

I could do a for loop and use .hasOwnProperty() but I want a better and smaller way to do it. I tried things like .includes , var v in obj, passing an array to .hasOwnProperty but nothing seems to work. 

const obj = {Password: '123456', Username: 'MeMyselfAndI'}
const checkFields= ['Method', 'Password', 'Username']
return checkIfObjectHaveKeysOfArray(obj, checkFields) // should return false because object doesn't have property 'Method'

Is there a way to do that without using a for loop? If yes, how?

Upvotes: 0

Views: 794

Answers (2)

Nina Scholz
Nina Scholz

Reputation: 386868

You could use Object.hasOwnProperty and check every key.

const
    object = { Password: '123456', Username: 'MeMyselfAndI' },
    checkFields = ['Method', 'Password', 'Username'],
    hasAllKeys = checkFields.every({}.hasOwnProperty.bind(object));

console.log(hasAllKeys);

Upvotes: 0

T.J. Crowder
T.J. Crowder

Reputation: 1075755

I could do a for loop and use .hasOwnProperty() but I wan't a better and smaller way to do it

Loops aren't that big. :-) But you could use every with an arrow function:

return checkFields.every(key => obj.hasOwnProperty(key));

Live Example:

const obj = {Password: '123456', Username: 'MeMyselfAndI'}
const checkFields= ['Method', 'Password', 'Username']
const result = checkFields.every(key => obj.hasOwnProperty(key));
console.log(result); // false

Upvotes: 3

Related Questions