CODEWITHSUNDEEP
phparrayslaravellaravel-5eloquent
user10665294
user10665294

Reputation:

Laravel Inserting Data Only the Last List or Data

I want to insert the data specifically look at my page.

enter image description here

When I set time the data will be inserted. But what I have right now is the data that is inserted is the very last data on this table which is January-31-2019 how can I fix it so when I insert data, the data will insert any of the data that is list on the table.

Controller

public function insertSchedule(Request $request)
{
    $employeeTimeSet = new Schedule;
    $employeeTimeSet->employee_no = $request->input('hidEmployeeno');
    $employeeTimeSet->last_name = $request->input('hidEmployeeLast');
    $employeeTimeSet->first_name = $request->input('hidEmployeeFirst');
    $employeeTimeSet->date_today = $request->input('dateToday');
    $employeeTimeSet->time_in = $request->input('timeIn');
    $employeeTimeSet->time_out = $request->input('timeOut');
    $employeeTimeSet->save();

    $notification = array(
        'message' => 'Click PLAN TIME! Employee Time Set!',
        'alert-type' => 'success'
    );

    return redirect()->back()->with($notification, 'Employee Time Set');
}

View

{!! Form::open(['action' => 'Admin\EmployeeFilemController@insertSchedule', 'method' => 'POST']) !!}
<div class="row">
    <div class="form-group col-md-12">
        <small>Employee No. and Name:</small>
        <b><i> {{ $employee->employee_no }} : {{ $employee->last_name }}, {{ $employee->first_name }}</i></b>
        <input type="hidden" name="hidEmployeeno" value='<?php echo $employee->employee_no ?>'>
        <input type="hidden" name="hidEmployeeLast" value='<?php echo $employee->last_name ?>'>
        <input type="hidden" name="hidEmployeeFirst" value='<?php echo $employee->first_name ?>'>
        <hr>
    </div>
</div>
@php
    $today = today(); 
    $dates = []; 

    for($i=1; $i < $today->daysInMonth + 1; ++$i) {
        $dates[] = \Carbon\Carbon::createFromDate($today->year, $today->month, $i)->format('F-d-Y');
    }
@endphp

<table class="table">
    <thead>
    <tr>
        <th>DATE TODAY</th>
        <th>TIME IN</th>
        <th>TIME OUT</th>
        <th>ACTION</th>
    </tr>
    </thead>
    <tbody>
    @foreach($dates as $date)
        <tr>
            <td><b>{{ $date }}</b></td>
            <input type="hidden" name="dateToday" value="{{ $date }}">
            <td><input type="time" name="timeIn" class="form-control col-md-10"></td>
            <td><input type="time" name="timeOut" class="form-control col-md-10"></td>
            <td> {{Form::button('<i class="fa fa-clock">&nbsp;&nbsp;SET TIME</i>',['type' => 'submit','class' => 'btn btn-warning btn-sm',  'style'=>"display: inline-block;"])}}</td>
        </tr>
    @endforeach
    </tbody>
</table>
{!! Form::close() !!}

Upvotes: 0

Views: 555

Answers (3)

ahmednawazbutt
ahmednawazbutt

Reputation: 833

In Addition to the @Swaroop's Answer there is another option. You can make array of these fields in the same form and submit them. and at the server end, you will have to loop through posted array so that you can process them further.

Upvotes: 0

Swaroop Deval
Swaroop Deval

Reputation: 906

The issue is that you are using one form with multiple inputs in it and there is no unique name to them. If you inspect the code, your form will have 31 inputs with name timeIn and 31 inputs with name timeOut.

When you submit the form, It picks the last timeIn and timeOut.

Two soluctions

  1. Make multiple forms (put form tags in while loop, it will create 31 forms in the page)
  2. Use ajax to send data to the server.

Upvotes: 2

Iynga Iyngaran Iyathurai
Iynga Iyngaran Iyathurai

Reputation: 842

You need to use [] for your textbox names. Example : name[] and you need to use a loop to post it. Example - how to get post from same name textboxes in php

Upvotes: 0

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