CODEWITHSUNDEEP
javaregex
Ankuj
Ankuj

Reputation: 723

Regex now finding all matching strings

I am using this regex ("http:|"https:)\/\/.*\/content\/amc\/tdd\/.*?" to find all the urls which starts with http or https and contains /content/amc/tdd But for the text

"<a id='cdq_element_175_link' href='http://google.com' data-href='edit' >
<img src=\"http://localhost:8080/content/amc/tdd/abc/download_1.jpeg? 
ch_ck=1548843340209\" alt=\"\" id=\"element_175\" style=\"height: 135.575px; width: 135.575px;\" data-href=\"edit\">
<img src=\"http://localhost:8080/content/amc/tdd/abc/download_1.jpeg?ch_ck=1548843340209\" alt=\"\" id=\"element_175\" style=\"height: 135.575px; width: 135.575px;\" data-href=\"edit\">
</a>"

I am not getting two strings which matches the pattern, instead I am getting the complete string starting from first instance to the last.

What am I doing wrong ?

Upvotes: 0

Views: 52

Answers (2)

Gurmanjot Singh
Gurmanjot Singh

Reputation: 10360

Try this Regex:

"https?:\/\/(?:[^\/]*\/)*?content\/amc\/tdd[^"]*"

Click for Demo

Explanation:

  • "https?:\/\/ - matches "http:// or "https://
  • (?:[^\/]*\/)*? - matches 0+ occurrences of any character which is not a / followed by /. This subpattern is repeated 0 or more times, as least as possible.
  • content\/amc\/tdd - matches content/amc/tdd
  • [^"]*" - matches 0+ occurrences of any character that is not a " followed by "

Upvotes: 2

thang
thang

Reputation: 343

Because inside your regex .* is greedy match, it will eat all your string.

You should change it to .*? Like this:

("http:|"https:)\/\/.*?\/content\/amc\/tdd\/.*?"

Upvotes: 2

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