Reputation: 241
I have a dataframe column with datetime data in 1980-12-11T00:00:00
format.
I need to convert the whole column to DD/MM/YYY
string format.
Is there any easy code for this?
Upvotes: 1
Views: 1437
Reputation: 91
You can use pd.to_datetime
to convert string to datetime data
pd.to_datetime(df['col'])
You can also pass specific format as:
pd.to_datetime(df['col']).dt.strftime('%d/%m/%Y')
Upvotes: 1
Reputation: 75080
Creating a working example:
df = pd.DataFrame({'date':['1980-12-11T00:00:00', '1990-12-11T00:00:00', '2000-12-11T00:00:00']})
print(df)
date
0 1980-12-11T00:00:00
1 1990-12-11T00:00:00
2 2000-12-11T00:00:00
Convert the column to datetime
by pd.to_datetime()
and invoke strftime()
df['date_new']=pd.to_datetime(df.date).dt.strftime('%d/%m/%Y')
print(df)
date date_new
0 1980-12-11T00:00:00 11/12/1980
1 1990-12-11T00:00:00 11/12/1990
2 2000-12-11T00:00:00 11/12/2000
Upvotes: 1
Reputation: 29742
When using pandas
, try pandas.to_datetime
:
import pandas as pd
df = pd.DataFrame({'date': ['1980-12-%sT00:00:00'%i for i in range(10,20)]})
df.date = pd.to_datetime(df.date).dt.strftime("%d/%m/%Y")
print(df)
date
0 10/12/1980
1 11/12/1980
2 12/12/1980
3 13/12/1980
4 14/12/1980
5 15/12/1980
6 16/12/1980
7 17/12/1980
8 18/12/1980
9 19/12/1980
Upvotes: 0