CODEWITHSUNDEEP
bashcut
bewolf
bewolf

Reputation: 165

How to save the cut command result in a file

my question is simple:

I used :

for file in `/path/*_aa.fasta.aln; do cut -f 1 -d "|" ${file} > ${file}.1; done`

Here as you can see I store the result in the ${file}.1 but how to juste do it on ${file} directly ?

Upvotes: 0

Views: 2640

Answers (2)

KamilCuk
KamilCuk

Reputation: 141493

As you can't read and write to a file sumltanously, you need to save/buffer the output, then output (the output) to the file.

Example like (this removes/adds only one trailing empty newlines):

cmd file | { buf=$(cat); printf "%s\n" "$buf" } > file

or:

temp=$(mktemp)
cmd file > "$temp"
mv "$temp" file

or if you have sponge which does exactly that:

cmd file | sponge file

So you can:

for file in /path/*_aa.fasta.aln; do 
    cut -f 1 -d "|" ${file} > ${file}.1
    mv ${file}.1 ${file}
done

or if you have sponge:

for file in /path/*_aa.fasta.aln; do 
    cut -f 1 -d "|" "${file}" | sponge "${file}"
done

Note: don't use backquotes ` `. Use command substitution $( ... ). Backquotes are deprecated, unreadable and become more unreadable when nested.

Upvotes: 1

brunorey
brunorey

Reputation: 2255

Try this:

for file in "/path/*_aa.fasta.aln";
do 
    cut -f 1 -d "|" ${file} > ${file}.tmp; 
    mv  ${file}.tmp ${file}; 
done

Upvotes: 1

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