CODEWITHSUNDEEP
pythonpython-2.7sortingdictionaryordereddict
wsh25
wsh25

Reputation: 55

How to sort a dict by the values inside its keys?

So I have something like this:

[
{
    "arg1":
          {"valueone" : 2, "valuetwo": 5"},
},
{
    "arg2":
          {"valueone" : 7, "valuetwo": 3"},
},
{
    "arg3":
          {"valueone" : 3, "valuetwo": 7"},
},
{
    "arg4":
          {"valueone" : 4, "valuetwo": 6"},
},
{
    "arg5":
          {"valueone" : 9, "valuetwo": 5"},
},

]

I want to sort them by their valueone s. I have a knowledge of OrderedDict, however I got some troubles to do this.

An expected result would be:

[
{
    "arg5":
          {"valueone" : 9, "valuetwo": 5"},
},
{
    "arg2":
          {"valueone" : 7, "valuetwo": 3"},
},
{
    "arg4":
          {"valueone" : 4, "valuetwo": 6"},
},
{
    "arg3":
          {"valueone" : 3, "valuetwo": 7"},
},

{
    "arg1":
          {"valueone" : 2, "valuetwo": 5"},
},


]

Any helps would be appreciated.

Upvotes: 1

Views: 74

Answers (2)

han solo
han solo

Reputation: 6590

Edit: Since python3, dict.keys() is not subscriptable, so z.keys()[0] would fail. So best to use:

>>> res = sorted(x, key=lambda z: next(iter(z.values()))['valueone'], reverse=True)
>>> pprint.pprint(res)
[{'arg5': {'valueone': 9, 'valuetwo': '5'}},
 {'arg2': {'valueone': 7, 'valuetwo': '3'}},
 {'arg4': {'valueone': 4, 'valuetwo': '6'}},
 {'arg3': {'valueone': 3, 'valuetwo': '7'}},
 {'arg1': {'valueone': 2, 'valuetwo': '5'}}]

Try this

>>> import pprint
>>> pprint.pprint(x)
[{'arg1': {'valueone': 2, 'valuetwo': 5}},
 {'arg2': {'valueone': 7, 'valuetwo': 3}},
 {'arg3': {'valueone': 3, 'valuetwo': 7}},
 {'arg4': {'valueone': 4, 'valuetwo': 6}},
 {'arg5': {'valueone': 9, 'valuetwo': 5}}]
>>> sorted_ = sorted(x, key=lambda z: z[z.keys()[0]]['valueone'], reverse=True)
>>> pprint.pprint(sorted_)
[{'arg5': {'valueone': 9, 'valuetwo': 5}},
 {'arg2': {'valueone': 7, 'valuetwo': 3}},
 {'arg4': {'valueone': 4, 'valuetwo': 6}},
 {'arg3': {'valueone': 3, 'valuetwo': 7}},
 {'arg1': {'valueone': 2, 'valuetwo': 5}}]

Upvotes: 2

Dani Mesejo
Dani Mesejo

Reputation: 61910

You could use the key parameter of sorted combined with reverse=True, for instance:

data = [
    {"arg1": {"valueone": 2, "valuetwo": "5"}},
    {"arg2": {"valueone": 7, "valuetwo": "3"}},
    {"arg3": {"valueone": 3, "valuetwo": "7"}},
    {"arg4": {"valueone": 4, "valuetwo": "6"}},
    {"arg5": {"valueone": 9, "valuetwo": "5"}}
]

result = sorted(data, key=lambda x: next(x["valueone"] for x in x.values()), reverse=True)
print(result)

Output

[{'arg5': {'valuetwo': '5', 'valueone': 9}}, {'arg2': {'valuetwo': '3', 'valueone': 7}}, {'arg4': {'valuetwo': '6', 'valueone': 4}}, {'arg3': {'valuetwo': '7', 'valueone': 3}}, {'arg1': {'valuetwo': '5', 'valueone': 2}}]

Upvotes: 2

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