CODEWITHSUNDEEP
bashshellscripting
Finalmix6
Finalmix6

Reputation: 415

Show the content of a file by its name

I'm trying to build a script that ask for user to type the name of the file, and once written, it simply shows what is inside this file, entirely.

So for instance,

Let's say I have a directory located in, /home/evaluation/, which contains severals files :

In /home/evaluation/file01, 

Lorem ipsum dolor sit amet.

In /home/evaluation/file02, 

Lorem ipsum sit amet.

In /home/evaluation/file03,

Lorem ipsum dolor

I'm looking forward to build a script that will ask me to write, the file name, I want to read, and once this file written, it will show all its content.

So if I type : file01, it will show me : 

Lorem ipsum dolor sit amet.

Else, if the file doesn't exist in the directory, then it shall be written : "no file found".

Upvotes: 0

Views: 287

Answers (1)

nPn
nPn

Reputation: 16758

Try this and see if you get what you are looking for

#!/bin/bash
echo Enter file name  # ask for the file name
read fileName  # get the a file name from the user and store it in fileName
if [ ! -f $fileName ] ; then  # check to see if the file exists
   echo "File not found"  # print a message if it does not
   exit  # all done so exit 
fi
# cat the file if we are still here , ie the file exists
cat $fileName

if [] in bash defines a test so and -f file_name checks to see if the file exists and is a regular file so [ ! -f $fileName ] will be true if the file does not exist, so then the message will be printed, otherwise the contents will be printed

Upvotes: 2

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