CODEWITHSUNDEEP
javaexception
Sachin Doiphode
Sachin Doiphode

Reputation: 433

How to throw exception for statment?

HI ! I want to throw exception for the line

BarcodeNo=Long.parseLong(jTextField1.getText())

I done this in a way 

BarcodeNo=Long.parseLong(jTextField1.getText()) throw new NumberFormatException("Enter Numbers Only ");

But this way compiler throws error stating ";" required

So anyone can tell me how to do this ?

Thanks

Upvotes: 0

Views: 588

Answers (2)

Ankur
Ankur

Reputation: 788

yes you should put

try
{
BarcodeNo=Long.parseLong(jTextField1.getText());
}
catch(Exception e)
{
throw new NumberFormatException("Enter Numbers Only ");

}

Upvotes: -1

Jon Skeet
Jon Skeet

Reputation: 1503230

That will already thrown an exception if the text isn't in the right format. If you want to change the exception message, you'd have to catch the exception and throw a new one:

try {
  BarcodeNo = Long.parseLong(jTextField1.getText());
} catch (NumberFormatException e) {
  throw new NumberFormatException("Enter Numbers Only");
}

I wouldn't suggest that you try to use exception message as user-visible messages though - they're more reasonable for logging than for showing an end user.

Upvotes: 2

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