Reputation: 5117
In python 3.3 and later, when we override __new__()
, we don't have to pass arguments and keyword arguments to super().__new__()
or object.__new__()
. But this call to super().__new__()
returns an instance of a class.
How does python pass the rest of the arguments to __init__
then?
class Spam(object):
''' Hello I am Spam '''
def __new__(cls, *args, **kwargs):
print("Creating Instance")
instance = object.__new__(cls) # Who passed *args and **kwargs to __init__?
print(instance)
return instance
def __init__(self, a, b):
print("Init Called")
self.a = a
self.b = b
Can someone please explain whats happening here?
Upvotes: 2
Views: 1309
Reputation: 41116
You passed cls as an argument to object.__new__, so the interpreter can check whether instance is an instance of cls.
The initializer (__init__) is automatically called by the allocator (__new__) as [Python.Docs]: object.__new__(cls[, ...]) states (emphases are mine):
If __new__() returns an instance of cls, then the new instance’s __init__() method will be invoked like
__init__(self[, ...])
, where self is the new instance and the remaining arguments are the same as were passed to __new__().If __new__() does not return an instance of cls, then the new instance’s __init__() method will not be invoked.
code00.py:
#!/usr/bin/env python3
import sys
class Spam(object):
''' Hello I am Spam '''
def __new__(cls, *args, **kwargs):
print("Creating Instance")
instance = object.__new__(cls) # Who passed *args and **kwargs to __init__?
print(instance)
#return instance # If you return anything else (1, object(), or None by commenting the line) here, __init__ won't be called
if len(sys.argv) == 1: # DO NOT DO THIS!!! It's just for demo purposes
return instance
def __init__(self, a, b):
print("Init Called")
self.a = a
self.b = b
def main():
spam = Spam(1, 2)
print(type(spam), dir(spam))
if __name__ == "__main__":
print("Python {0:s} on {0:s}\n".format(sys.version, sys.platform))
main()
Output:
e:\Work\Dev\StackOverflow\q054511671>"e:\Work\Dev\VEnvs\py_064_03.06.08_test0\Scripts\python.exe" code00.py Python 3.6.8 (tags/v3.6.8:3c6b436a57, Dec 24 2018, 00:16:47) [MSC v.1916 64 bit (AMD64)] on win32 Creating Instance <__main__.Spam object at 0x000001F8E24D14E0> Init Called <class '__main__.Spam'> ['__class__', '__delattr__', '__dict__', '__dir__', '__doc__', '__eq__', '__format__', '__ge__', '__getattribute__', '__gt__', '__hash__', '__init__', '__init_subclass__', '__le__', '__lt__', '__module__', '__ne__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__', '__weakref__', 'a', 'b'] e:\Work\Dev\StackOverflow\q054511671>"e:\Work\Dev\VEnvs\py_064_03.06.08_test0\Scripts\python.exe" code.py arg Python 3.6.8 (tags/v3.6.8:3c6b436a57, Dec 24 2018, 00:16:47) [MSC v.1916 64 bit (AMD64)] on win32 Creating Instance <__main__.Spam object at 0x0000020808F71550> <class 'NoneType'> ['__bool__', '__class__', '__delattr__', '__dir__', '__doc__', '__eq__', '__format__', '__ge__', '__getattribute__', '__gt__', '__hash__', '__init__', '__init_subclass__', '__le__', '__lt__', '__ne__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__']
Note that this isn't specific to Python 3 (check [Python 2.Docs]: Data model), but rather to [Python]: New-style Classes For more details, you could also check check [Python 2.2.Docs]: Overriding the __new__ method (the Singleton class).
Upvotes: 2
Reputation: 148890
What matters here is the initial call, say spam = Spam('x', 1)
.
Internally, Python calls __new__
as a class method on class Spam
with the passed parameters. What Spam.__new__
actually does is not really important, it is just supposed to return an object.
It does use object.__new__
to build a Spam
object. As the created object has the correct class, Python calls __init__
on it with the initial parameters.
Upvotes: 1