Samnang
Samnang

Reputation: 5616

capybara: page.should have_no_content doesn't work correctly for display:none element

I would like to use page.should have_no_content to check if the page doesn't display the label to user, here what it is in HTML:

<li id="account_input" style="display: none;">
    <label for="account_name">My Account</label>
    ...
</li>

So when I use page.should have_no_content("My Account"), it returns false instead of true.

Upvotes: 8

Views: 8675

Answers (4)

AndPy
AndPy

Reputation: 406

So when I use page.should have_no_content("My Account"), it returns false instead of true.

It should be false. Think about it this way: if your page does have the content "My account", then have_content would return True, thus have_no_content should return False. And the reason - it is not true to say that the HTML does not have the content "My account" in it. Thus, it is False.

Upvotes: -1

Volatil3
Volatil3

Reputation: 14978

I found another way to implement should not have

page.should_not( have_content(arg1))

Upvotes: 0

Samnang
Samnang

Reputation: 5616

I found a solution using:

Then /^"([^\"]+)" should not be visible$/ do |text|
  paths = [
    "//*[@class='hidden']/*[contains(.,'#{text}')]",
    "//*[@class='invisible']/*[contains(.,'#{text}')]",
    "//*[@style='display: none;']/*[contains(.,'#{text}')]"
  ]
  xpath = paths.join '|'
  page.should have_xpath(xpath)
end

Upvotes: 3

Shiv
Shiv

Reputation: 8412

You could use this statement

find('#account_input').should_not be_visible

Upvotes: 12

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