CODEWITHSUNDEEP
pythonlist
dexter7d
dexter7d

Reputation: 23

Slicing nested list. Explanation

x = [1,[2,[3,4],5],6]
print(x[1][1][1])

Could you explain it to me, why the result is 4.

Upvotes: 1

Views: 142

Answers (4)

matiit
matiit

Reputation: 8017

x = [1,[2,[3,4],5],6]

What x[1][1][1] does is:

Takes the second element:

[2,[3,4],5]

second element from that list:

[3,4]

second element

4

So it makes perfect sense.

It's the second not first element because lists in python are numerated from 0.

Upvotes: 0

Jay
Jay

Reputation: 24905

x = [1,[2,[3,4],5],6]

is actually like below when you look at it as index based:

InnerList-2 Index->       0 1
InnerList-1 Index->    0 1     2
OuterList Index->   0 1           2
x =                [1,[2,[3,4],5],6]

So, this translates to:

x[1] ->    [2,[3,4],5]
x[1][1] -> [3,4]
x[1][1] -> 4

Upvotes: 0

theSekyi
theSekyi

Reputation: 530

x = [1,[2,[3,4],5],6]

x[1] = [2,[3,4],5]

x[1][1] = [3,4]

x[1][1][1] = 4

Remember you start indexing from 0. So x[0] = 1 and x[1] = the entire nested list

Also remember that a nested list is detected as a single entity. In this case, x contains 3 elements which are 1,[2,[3,4],5] and 6. The second element now has an index position of 1 and also contains 3 elements which are 2,[3,4] and 5. Same for the nested loop [3,4].

Upvotes: 0

DirtyBit
DirtyBit

Reputation: 16792

Since indices is 0 based.

x = [1,[2,[3,4],5],6]

# The element placed on 1 of [1,[2,[3,4],5],6] i.e. [2, [3, 4], 5]
print(x[1])  

# The element placed on 1 of [2, [3, 4], 5] i.e.  [3, 4]
print(x[1][1]) 

# The element placed on 1 of [3, 4] i.e. 4
print(x[1][1][1])

OUTPUT:

[2, [3, 4], 5]
[3, 4]
4

Upvotes: 2

Related Questions