CODEWITHSUNDEEP
sql-serversql-server-2008-r2
MAK
MAK

Reputation: 7260

Check only specific field present in the string

I want to print the one of the following condition string if it contains only number field.

DECLARE @Condition varchar(max) = 'Number =''12908,13232323,12122'' AND Name=''Mak'''

DECLARE @Condition1 varchar(max) = 'Address=''UK'' AND Number =''12908'' AND Name=''Mak'''

DECLARE @Condition2 varchar(max) = 'Number =''12908,13232323'''

Note: The condition string is dynamic may comes with any number of fields but I want print it only if it contain number.

Expected Result: From the given condition2 should be print.

Number = '12908,13232323'

Upvotes: 0

Views: 54

Answers (3)

level3looper
level3looper

Reputation: 1051

Using Like to find 'Number' without 'AND'. 

DECLARE @Condition varchar(max) = 'Number =''12908,13232323,12122'' AND Name=''Mak'''
DECLARE @Condition1 varchar(max) = 'Address=''UK'' AND Number =''12908'' AND Name=''Mak'''
DECLARE @Condition2 varchar(max) = 'Number =''12908,13232323'''

Query

Select conditions From (Values (@Condition),(@Condition1),(@Condition2)) c(conditions)
Where conditions Like '%Number%' And conditions Not Like '%AND%'

Upvotes: 1

MAK
MAK

Reputation: 7260

Tried the following and does the job done.

DECLARE @Condition varchar(max) = 'Number =''12908,13232323,12122'' AND Name=''Mak'''

DECLARE @Condition1 varchar(max) = 'Address=''UK'' OR Number =''12908'' AND Name=''Mak'''

DECLARE @Condition2 varchar(max) = 'Number =''12908,13232323'''

IF REPLACE(REPLACE(@Condition,' OR ',' @ '),' AND ',' @ ') NOT LIKE '%@%' 
BEGIN
    PRINT(@Condition);
END
ELSE IF REPLACE(REPLACE(@Condition1,' OR ',' @ '),' AND ',' @ ') NOT LIKE '%@%' 
BEGIn
    PRINT(@Condition1);
END
ELSE IF REPLACE(REPLACE(@Condition2,' OR ',' @ '),' AND ',' @ ') NOT LIKE '%@%'  
BEGIn
    PRINT(@Condition2);
END
ELSE
BEGIN
    PRINT('none');
END

Upvotes: 0

Matthew Baker
Matthew Baker

Reputation: 2729

I use a cte split function

CREATE function [dbo].[fn_string_split](@str NVARCHAR(MAX)
, @delimiter NVARCHAR(255))
returns table
as
return
WITH a AS(
        SELECT CAST(0 AS BIGINT) as idx1,CHARINDEX(@delimiter,@str) idx2
        UNION ALL
        SELECT idx2+1,CHARINDEX(@delimiter,@str,idx2+1)
        FROM a
        WHERE idx2>0
    )
    SELECT SUBSTRING(@str,idx1,COALESCE(NULLIF(idx2,0),LEN(@str)+1)-idx1) as value, row_number() over (Order by idx1) RN
    FROM a

This was then leveraged against your data to identify number of conditions in each string, and then filter.

DECLARE @Condition varchar(max) = 'Number =''12908,13232323,12122'' AND Name=''Mak'''

DECLARE @Condition1 varchar(max) = 'Address=''UK'' AND Number =''12908'' AND Name=''Mak'''

DECLARE @Condition2 varchar(max) = 'Number =''12908,13232323'''

DECLARE @Table AS TABLE (ID INT, Condition varchar(MAX))
INSERT INTO @Table VALUES
(0,@Condition),(1,@Condition1),(2,@Condition2);

WITH CTE AS (
SELECT T.*, C.value,COUNT(1) OVER (PARTITION BY ID) Cnt
FROM @Table T
CROSS APPLY dbo.fn_string_split(Condition,'AND') C 
)
SELECT * FROM cte WHERE Cnt=1 AND LEFT(REPLACE(value,' ',''),7) = 'Number='

Could do with some more tweaking to exclude outlying cases but hopefully this will get you started.

Upvotes: 2

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